Question

6. Given the following equations:
(i) 3 A2+ + 2 D → 3 A + 2 D3+

(ii) D + 3 B+ → D3+ + 3 B

(iii) 2 C + 3 A2+ → 2 C3+ + 3 A
Arrange the elements A, B, C, and D from the strongest to weakest reducing agent.

Answer 1

In the reaction i) D is reducing A2+ to A and itself oxidized to D3+

In the reaction ii) D is reducing B+ to B and itself oxidized to D3+

In the reaction iii) C is reducing A2+ to A and itself oxidized to C3+

so from these three reactions, it can be said that D is the strongest reducing agent and A is the weakest reducing agent.

So, the order is

D>C>B>A