Question

I need this code in java.

Loops do just what they sound like they should - they perform a statement again and again until a condition is fulfilled.

For this lab you will be practicing using loops, specifically a for loop.

The for loop takes the form of:

for(/*variable initialization*/;/*stop condition*/; /*increment*/){
    //statements to be done multiple times
}

Task

Write an application that displays every perfect number from 2 through 1,000. A perfect number is one that equals the sum of all the numbers that divide evenly into it. For example, 6 is perfect because 1, 2, and 3 divide evenly into it and their sum is 6; however, 12 is not a perfect number because 1, 2, 3, 4, and 6 divide evenly into it, and their sum is greater than 12.

The provided template lays out the initial for loop to check each number beginning from 2 and going up to 1,000. In this for loop, the perfect() method is called, where you will submit your piece of code to test if each number follows the conditions described above.

Set result to true if it meets those conditions and use sum to add up the numbers divisible by int n in the method's parameter.

this is what I have so far:

public class Perfect{
public static void main (String args[]){
final int MAX = 1000;
for(int i = 2; i <= MAX; i++)
if(perfect(i) == true)
System.out.println("The number " + i + " is perfect");
  
}
public static boolean perfect(int n){
int sum = 1;
boolean result = false;
// And then I know I need to insert the rest but it always comes out wrong here
  
return result;
}
}

Please edit the code I have started, thank you.

Answer 1

public class Perfect {
   public static void main(String args[]) {
       final int MAX = 1000;
       for (int i = 2; i <= MAX; i++)
           if (perfect(i) == true)
               System.out.println("The number " + i + " is perfect");

   }

   public static boolean perfect(int n) {
       int sum = 0;
       boolean result = false;
       //looping through numbers from 1 to n
       //adding factors it sum
       for (int i = 1; i < n; i++) {
           if (n % i == 0)
               sum += i;
       }
       result = (sum == n);
       return result;
   }
}

Note : Please comment below if you have concerns. I am here to help you

If you like my answer please rate and help me it is very Imp for me