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The )G01 for the hydrolysis of phosphorarginine reaction depicted below is –32 kJ mol-1.       Phosphoarginine  ...

  1. The )G01 for the hydrolysis of phosphorarginine reaction depicted below is –32 kJ mol-1.      

Phosphoarginine   +   H2O    →     Arginine    +     Pi

What is the free-energy change, )G, for the reaction in lobster muscle at 5oC and pH 7.0 when the concentrations of phosphoarginine, arginine and Pi are 6.1mM, 2.4mM and 5.7mM, respectively?

(R = 8.315 J/molK)

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Answer #1

For given reaction

Q = [arginine] [Pi] / [Phosphoarginine] = 2.4mM * 5.7 mM / 6.1mM = 2.2 mM

G =Go + RT ln Q = -32 kJ/mol + (8.315 J/mol.K * 273 K)ln (2.2*10-3) = -32 kJ/mol -13,847.22 J/mol

G = -32 kJ/mol -13.8 kJ/mol = -45.8 kJ/mol

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