Question

A pebble with mass m is thrown straight up with an initial speed v₀ so that its maximum altitude is h. Where will it land? Discuss the difference between this case and one discussed in class of the pebble dropped from a height h.

Answer 1

The time taken by the pebble from maximum height to reach the ground is

t =  sqrt ( 2 h / g )

The horizontal distance covered by the pubble

       R = v_x t

            = v_o   (sqrt ( 2 h / g ) )

Thus, the difference between this case and one discussed in the class of the pebble dropped from a height h v_o   (sqrt ( 2 h / g ) ).