How many moles of benzaldehyde (density d = 1.04 g/ml), (molecular weight mw = 106.12 g/mol)...
How many moles of benzaldehyde (density d = 1.04 g/ml), (molecular weight mw = 106.12 g/mol) are required to react with 1.0 ml of acetone: (density d = 0.79 g/ml), (molecular weight mw = 58.08 g/mol)? 6.
What is approximate theoretical yield for problem # 5 if you obtained 2.1 grams of dibenzylidene acetone (mw = 234.29 g/mol)?
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How many moles of benzaldehyde (density d = 1.04 g/ml),
(molecular weight mw = 106.12 g/mol)...
2 dibenzalacetone acetone benzaldehyde MW- 106.13 g/mol bp-1 78°C d 1.04 g/mL MW 234.30 g/mol mp #110-1110 MW-58.08 g/mol bp 56°C d 0.79 g/mL Its bs Reaction Setup (3 pts) S. OS Initial quant...
2 dibenzalacetone acetone benzaldehyde MW- 106.13 g/mol bp-1 78°C d 1.04 g/mL MW 234.30 g/mol mp #110-1110 MW-58.08 g/mol bp 56°C d 0.79 g/mL Its bs Reaction Setup (3 pts) S. OS Initial quantity of NaOH: S. I Initial quantity of benzaldehyde: mL Initial quantity of acetone: mL Theoretical yield of dibenzalacetone based on benzaldehyde: (show calculations) Theoretical yield of dibenzalacetone based on acetone 9 (show calculations) ce tone Limiting Reagent: Product Data (10 pts) fivAL Mass: 3.3g Percent Yield:...
8 2 H NaOH Еюн 5 benzaldehyde d 1.044 acetone d0.791 When doing part B of the reaction for lab, how many grams of b...
8 2 H NaOH Еюн 5 benzaldehyde d 1.044 acetone d0.791 When doing part B of the reaction for lab, how many grams of benzaldehyde (#4) would you need if you are trying to make a maximum theoretical yield of 15 grams of dibenzalacetone (#6)? Acetone: density 0.791 g/mL and molar mass 58.08 grams/mole Benzaldehyde: density 1.044 g/mL and molar mass 106.12 grams/mole Dibenzalacetone: molar mass = 234.29 grams/mole Enter answer.... со
Question 8 1 pts NAOH BOHO acetone d 0.791 benzaldehyde d 1.044 When doing part of...
Question 8 1 pts NAOH BOHO acetone d 0.791 benzaldehyde d 1.044 When doing part of the reaction for lab, how many grams of benzaldehyde (#4) would you need if you are trying to make a maximum theoretical yield of 10 grams of dibenzalacetone (#6)? Acetone: density = 0.791 g/mL and molar mass = 58.08 grams/mole Benzaldehyde: density - 1.044 g/mL and molar mass = 106.12 grams/mole Dibenzalacetone: molar mass = 234.29 grams/mole
1 pts Question 7 2 H NaOH EOH benzaldehyde d 1.044 acetone d 0.791 When doing...
1 pts Question 7 2 H NaOH EOH benzaldehyde d 1.044 acetone d 0.791 When doing part B of the reaction for lab, how many grams of acetone (#5) would you need if you are trying to make a maximum theoretical yield of 15 grams of dibenzalacetone (#6)? Acetone: density 0.791 g/mL and molar mass 58.08 grams/mole 1044 g/mL and molar mass 106.12 grams/mole Benzaldehyde: density Dibenzalacetone: molar mass 234.29 grams/mole
Compound Benzaldehyde Amount moles equivalents MW (g/mol) Density (g/mL) 106.1 138.2 102.1 K2CO3 ...
Question #1
Please Complete the following reagent table:
Compound Benzaldehyde Amount moles equivalents MW (g/mol) Density (g/mL) 106.1 138.2 102.1 K2CO3 Acetic anhydride trans-cinnamic acid (1) 4 K2CO3 C7HgO Mol. Wt.: 106.12 bp: 178°C C4H6O3 Mol. Wt.: 102.09 CgHgO2 Mol. Wt.: 148.16 bp: 140°C mp: 135°C
Compound Benzaldehyde Amount moles equivalents MW (g/mol) Density (g/mL) 106.1 138.2 102.1 K2CO3 Acetic anhydride trans-cinnamic acid (1) 4
K2CO3 C7HgO Mol. Wt.: 106.12 bp: 178°C C4H6O3 Mol. Wt.: 102.09 CgHgO2 Mol. Wt.: 148.16...
find limiting reagent? acetone 3.63 mL benzaldehyde 10.5mL bp (°C) mol. wt. (g/mole) 58.08 density (g/mL)...
find limiting reagent?
acetone 3.63 mL
benzaldehyde 10.5mL
bp (°C) mol. wt. (g/mole) 58.08 density (g/mL) 0.791 56 106.23 178-179 1.044 Acetone Benzaldehyde NaOH Dibenzalacetone 40.00 234.30 mp 110-111 9. Calculations for synthesis-moles of reactants, limiting reagent, theoretical yield , % experimental yield, show all math
Need help please. 22. I believe a. is 2 moles and b. is 2 moles 23....
Need help please.
22. I believe a. is 2 moles and b. is 2 moles
23. 2 moles of Ben gives 1 mole of product= which should equal
121.65 grams. But need help not sure if they are correct and I
don't know 24.
22. For the following Aldol Condensation: To make one mole of product, how many moles of each reactant are needed? 0. NaOH CH CHCCH CH FW-106.13 d-1.0415 grnL F-58.08 g/mol d-0.7899 gmL Mp 110.5-112 °C FW...
COLEMAS CRUNCIS Compound Mass M.W. Quantity in moles M.p. range or b.p. (°C) (g/mol) 106.13 Benzaldehyde...
COLEMAS CRUNCIS Compound Mass M.W. Quantity in moles M.p. range or b.p. (°C) (g/mol) 106.13 Benzaldehyde 0.212 0.00199755 Acetone 0.058 58.08 0.00099862 Dibenzalacetone 0.053 234.20 0.0002263 Lit: 110-111°C Actual: 75-80 Calculations of theoretical yield (based on limiting reagent) and crude and pure % yield: (4 prs
Please refer to the Aldol Condensation experiment in your lab manual (page 89) • Calculate the...
Please refer to the Aldol Condensation experiment in your lab manual (page 89) • Calculate the amounts of all chemicals needed in measurable amounts (i.e. grams or milliliters rather than moles.) • Determine the theoretical yield for the reaction. Mixture A: Prepare a solution of 5g of sodium hydroxide dissolved in Du and 40ml of ethanol at room temperature in a 250 ml Erlenmeyer flask. Mixture B: Mix 5.1 ml(5.31 g) of benzaldehyde (MW 106 g/mol; d = 1.04 g/ml)...
5.1 g of 1,4-di-t-butyl-2,5-dimethoxynezene (250.37 g/mol) were synthesized by reacting 9.7 mL of t-butyl alcohol (MW...
5.1 g of
1,4-di-t-butyl-2,5-dimethoxynezene
(250.37 g/mol) were synthesized by reacting
9.7 mL of t-butyl alcohol (MW 74.12 g/mol, D
0.79 g/mL), 25 mL of concentrated sulfuric
acid (MW 98.08 g/mol, D 1.84
g/mL), and 4.2 g of 1,4-dimethoxybenzene (MW
138.17 g/mol) together. Calculate the percent
yield of this reaction. Write your answer without a percent
sign and to 2 decimal places. MW=molecular weight, D=density of
liquid. PLEASE SHOW WORK
OH t-butanol 1,4-di-tert-butyl-2,5-dimethoxybenzene 1,4-dimethoxybenzene
2 dibenzalacetone acetone benzaldehyde MW- 106.13 g/mol bp-1 78°C d 1.04 g/mL MW 234.30 g/mol mp #110-1110 MW-58.08 g/mol bp 56°C d 0.79 g/mL Its bs Reaction Setup (3 pts) S. OS Initial quantity of NaOH: S. I Initial quantity of benzaldehyde: mL Initial quantity of acetone: mL Theoretical yield of dibenzalacetone based on benzaldehyde: (show calculations) Theoretical yield of dibenzalacetone based on acetone 9 (show calculations) ce tone Limiting Reagent: Product Data (10 pts) fivAL Mass: 3.3g Percent Yield:...
8 2 H NaOH Еюн 5 benzaldehyde d 1.044 acetone d0.791 When doing part B of the reaction for lab, how many grams of benzaldehyde (#4) would you need if you are trying to make a maximum theoretical yield of 15 grams of dibenzalacetone (#6)? Acetone: density 0.791 g/mL and molar mass 58.08 grams/mole Benzaldehyde: density 1.044 g/mL and molar mass 106.12 grams/mole Dibenzalacetone: molar mass = 234.29 grams/mole Enter answer.... со
Question 8 1 pts NAOH BOHO acetone d 0.791 benzaldehyde d 1.044 When doing part of the reaction for lab, how many grams of benzaldehyde (#4) would you need if you are trying to make a maximum theoretical yield of 10 grams of dibenzalacetone (#6)? Acetone: density = 0.791 g/mL and molar mass = 58.08 grams/mole Benzaldehyde: density - 1.044 g/mL and molar mass = 106.12 grams/mole Dibenzalacetone: molar mass = 234.29 grams/mole
1 pts Question 7 2 H NaOH EOH benzaldehyde d 1.044 acetone d 0.791 When doing part B of the reaction for lab, how many grams of acetone (#5) would you need if you are trying to make a maximum theoretical yield of 15 grams of dibenzalacetone (#6)? Acetone: density 0.791 g/mL and molar mass 58.08 grams/mole 1044 g/mL and molar mass 106.12 grams/mole Benzaldehyde: density Dibenzalacetone: molar mass 234.29 grams/mole
Question #1
Please Complete the following reagent table:
Compound Benzaldehyde Amount moles equivalents MW (g/mol) Density (g/mL) 106.1 138.2 102.1 K2CO3 Acetic anhydride trans-cinnamic acid (1) 4 K2CO3 C7HgO Mol. Wt.: 106.12 bp: 178°C C4H6O3 Mol. Wt.: 102.09 CgHgO2 Mol. Wt.: 148.16 bp: 140°C mp: 135°C
Compound Benzaldehyde Amount moles equivalents MW (g/mol) Density (g/mL) 106.1 138.2 102.1 K2CO3 Acetic anhydride trans-cinnamic acid (1) 4
K2CO3 C7HgO Mol. Wt.: 106.12 bp: 178°C C4H6O3 Mol. Wt.: 102.09 CgHgO2 Mol. Wt.: 148.16...
find limiting reagent?
acetone 3.63 mL
benzaldehyde 10.5mL
bp (°C) mol. wt. (g/mole) 58.08 density (g/mL) 0.791 56 106.23 178-179 1.044 Acetone Benzaldehyde NaOH Dibenzalacetone 40.00 234.30 mp 110-111 9. Calculations for synthesis-moles of reactants, limiting reagent, theoretical yield , % experimental yield, show all math
Need help please.
22. I believe a. is 2 moles and b. is 2 moles
23. 2 moles of Ben gives 1 mole of product= which should equal
121.65 grams. But need help not sure if they are correct and I
don't know 24.
22. For the following Aldol Condensation: To make one mole of product, how many moles of each reactant are needed? 0. NaOH CH CHCCH CH FW-106.13 d-1.0415 grnL F-58.08 g/mol d-0.7899 gmL Mp 110.5-112 °C FW...
COLEMAS CRUNCIS Compound Mass M.W. Quantity in moles M.p. range or b.p. (°C) (g/mol) 106.13 Benzaldehyde 0.212 0.00199755 Acetone 0.058 58.08 0.00099862 Dibenzalacetone 0.053 234.20 0.0002263 Lit: 110-111°C Actual: 75-80 Calculations of theoretical yield (based on limiting reagent) and crude and pure % yield: (4 prs
Please refer to the Aldol Condensation experiment in your lab manual (page 89) • Calculate the amounts of all chemicals needed in measurable amounts (i.e. grams or milliliters rather than moles.) • Determine the theoretical yield for the reaction. Mixture A: Prepare a solution of 5g of sodium hydroxide dissolved in Du and 40ml of ethanol at room temperature in a 250 ml Erlenmeyer flask. Mixture B: Mix 5.1 ml(5.31 g) of benzaldehyde (MW 106 g/mol; d = 1.04 g/ml)...
5.1 g of
1,4-di-t-butyl-2,5-dimethoxynezene
(250.37 g/mol) were synthesized by reacting
9.7 mL of t-butyl alcohol (MW 74.12 g/mol, D
0.79 g/mL), 25 mL of concentrated sulfuric
acid (MW 98.08 g/mol, D 1.84
g/mL), and 4.2 g of 1,4-dimethoxybenzene (MW
138.17 g/mol) together. Calculate the percent
yield of this reaction. Write your answer without a percent
sign and to 2 decimal places. MW=molecular weight, D=density of
liquid. PLEASE SHOW WORK
OH t-butanol 1,4-di-tert-butyl-2,5-dimethoxybenzene 1,4-dimethoxybenzene
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