Question

C++ Concepts: Single-Dimension Array

Write a program, using 25 or fewer lines of code, to count each occurrence of each lower-case letter in a string.

Start your program by declaring a character array, msg, with a size of 30 or greater.

char msg[MAX];

The user should then type a text string into the array:

cin.getline(msg, MAX);

Your program should now report the number of each character (a-z) found in the array:

a face at the beach

a - 4
b - 1
c - 2
d - 0
e - 3
f - 1
g - 0
h - 2
i - 0
j - 0
k - 0
l - 0
m - 0
n - 0
o - 0
p - 0
q - 0
r - 0
s - 0
t - 2
u - 0
v - 0
w - 0
x - 0
y - 0
z - 0

Here is one way of creating that output using characters in a loop:

for (i=0; i<26; i++)

cout << static_cast(i + 'a') << " - "
<< etc..

Answer 1

For counting the alphabets , we need to count the particular  alphabet by traversing the whole string . To do this, we need to use two loops - one for traversing the alphabets and the other for traversing the whole string .

CODE :

#include <iostream>

#define MAX 30 // defining the variable MAX as 30
using namespace std;

int main() {
  
   char msg[MAX] ; // declaring the char array with size 30
   cin.getline(msg,MAX) ; // taking input from the user
  
   for(int i =0;i<26;i++) // for traversing the alphabets from 'a ' to 'z' .
   {
   int count= 0; // for counting the no.of occurrences of the particular alphabet.
  

for(int j=0;j<MAX;j++) // for traversing the whole string
   {
  

if(static_cast<char>(i+'a')==msg[ j]) // checking the equality and incrementing the value of count
count++ ;

}
   cout << static_cast<char>(i + 'a') << " - " <<count<<endl;
   }

return 0;
}