Consider this balanced chemical equation: H2O2(aq)+3I−(aq)+2H+(aq)→I3−(aq)+2H2O(l)H2O2(aq)+3I−(aq)+2H+(aq)→I3−(aq)+2H2O(l) In the first 10.0 seconds of the reaction, the concentration...

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Consider this balanced chemical equation: H2O2(aq)+3I−(aq)+2H+(aq)→I3−(aq)+2H2O(l)H2O2(aq)+3I−(aq)+2H+(aq)→I3−(aq)+2H2O(l) In the first 10.0 seconds of the reaction, the concentration...

Consider this balanced chemical equation:

H2O2(aq)+3I−(aq)+2H+(aq)→I3−(aq)+2H2O(l)H2O2(aq)+3I−(aq)+2H+(aq)→I3−(aq)+2H2O(l)

In the first 10.0 seconds of the reaction, the concentration of I−I− drops from 1.260 MM to 0.877 MM.

Calculate the average rate of this reaction in this time interval.

Express your answer with the appropriate units.

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Answer 1

Answer #1

average rate = change in concentration /change in time
= - [0.877 mM - 1.260 mM]/10 s - 0 s

rate must be positive always and since there is a decrease in
concentration we include negative sign.

Average rate = 0.0383 mM/s
*****************************

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Answer 2

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Consider this balanced chemical equation: H2O2(aq)+3I−(aq)+2H+(aq)→I3−(aq)+2H2O(l)H2O2(aq)+3I−(aq)+2H+(aq)→I3−(aq)+2H2O(l) In the first 10.0 seconds of the reaction, the concentration...

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Add Answer to: Consider this balanced chemical equation: H2O2(aq)+3I−(aq)+2H+(aq)→I3−(aq)+2H2O(l)H2O2(aq)+3I−(aq)+2H+(aq)→I3−(aq)+2H2O(l) In the first 10.0 seconds of the reaction, the concentration...

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Add Answer to:
Consider this balanced chemical equation: H2O2(aq)+3I−(aq)+2H+(aq)→I3−(aq)+2H2O(l)H2O2(aq)+3I−(aq)+2H+(aq)→I3−(aq)+2H2O(l) In the first 10.0 seconds of the reaction, the concentration...