A population of values has a normal distribution with μ=207.3 and σ=35.8. A random sample of size n=103 is drawn. Find the probability that a sample of size n=103 is randomly selected with a mean less than 208.4. Round your answer to four decimal places.
P(M<208.4)=
Solution :
Given that ,
mean =
= 207.3
standard deviation =
= 35.8.
n = 103

= 207.3

=
/
n = 35.8/
103=3.53
P(M <208.4 ) = P[(M -
) /
< (208.4-207.3) /3.53 ]
= P(z <0.31 )
Using z table
= 0.6217
probability= 0.6217
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