The highway department wants to estimate the proportion of
vehicles on Interstate 25 between the hours of midnight and 5:00
A.M. that are 18-wheel tractor trailers. The estimate will be used
to determine highway repair and construction considerations and in
highway patrol planning. Suppose researchers for the highway
department counted vehicles at different locations on the
interstate for several nights during this time period. Of the 3,367
vehicles counted, 971 were 18-wheelers.
a. Determine the point estimate for the proportion
of vehicles traveling Interstate 25 during this time period that
are 18-wheelers.
b. Construct a 99% confidence interval for the
proportion of vehicles on Interstate 25 during this time period
that are 18-wheelers.
(Round your answers to 3 decimal
places.)
a. The point estimate is __________
b. _______ ≤ p ≤ ________
a)
The point estimate = 971/3367 = 0.2884
b)
sample size, n = 3367
Standard error, SE = sqrt(pcap * (1 - pcap)/n)
SE = sqrt(0.2884 * (1 - 0.2884)/3367) = 0.008
Given CI level is 99%, hence α = 1 - 0.99 = 0.01
α/2 = 0.01/2 = 0.005, Zc = Z(α/2) = 2.58
Margin of Error, ME = zc * SE
ME = 2.58 * 0.008
ME = 0.0206
CI = (pcap - z*SE, pcap + z*SE)
CI = (0.2884 - 2.58 * 0.008 , 0.2884 + 2.58 * 0.008)
CI = (0.268 , 0.309)
0.268 <= p < = 0.309
The highway department wants to estimate the proportion of vehicles on Interstate 25 between the hours...
The highway department wants to estimate the proportion of vehicles on Interstate 25 between the hours of midnight and 5:00 A.M. that are 18-wheel tractor trailers. The estimate will be used to determine highway repair and construction considerations and in highway patrol planning. Suppose researchers for the highway department counted vehicles at different locations on the interstate for several nights during this time period. Of the 3,593 vehicles counted, 883 were 18-wheelers. a. Determine the point estimate for the proportion...
Question 25 (1 point) A crew of mechanics at the Hamilton Highway Department garage repair vehicles that break down at an average of = 9.9 vehicles per day (approximately Poisson in nature). The mechanic crew can service an average of u = 11.9 vehicles per day with a repair time distribution that approximates an exponential distribution (the entire crew works on one vehicle at a time). How many vehicles are likely to be waiting for service at any one time?...