Question

Please help and answer all, thank you!

Calculate the molarity of each solution.

Part A

1.37 mol of LiCl in 33.8 L of solution

Express your answer using three significant figures.

Part B

0.110 mol of LiNO3 in 8.0 L of solution

Express your answer using two significant figures.

Part C

0.0313 mol of glucose in 89.2 mL of solution

Express your answer using three significant figures.

Answer 1

Molarity = number of moles of solute / volume of solution in litre

Part A

Molarity = 1.37 mol / 33.8 L = 0.04 mol/L = 0.04 M

Part B

Molarity = 0.110 mol / 8.0 L = 0.014 mol/L = 0.014 M

Part C

Volume of solution = 89.2 ml = 89.2 L / 1000 = 0.0892 L

Molarity = 0.0313 mol / 0.0892 L = 0.35 mol/L = 0.35 M