Question

Calculate the molarity of each of the following solutions.

Part A 0.35 mol of LiNO3 in 6.16 L of solution

Express your answer using two significant figures.

Part B: 72.2 g C2H6O in 2.22 L of solution

Express your answer using three significant figures.

Part C: 11.29 mg KI in 108.6 m of solution

Express your answer using four significant figures.

Answer 1

the molarity of each of the following 3) Calculate Solutions Answer :- Molarity = No. of moles of solute. vol. (litre) of solution Molarity - No. of moles of solute in Litre of solution. Part A No. of moles of LiNO3 = 0.35 mole volume Ola solution in litre = 6.164 Molarity = 0.35 mol _ 0.0568 moll 6.162 568 ml Maarity = 0.057 mol/L answer part B - No. of moles - wt.ingram (soleste) Molale mals wt of Solete = 72.2 gm C2HGO Molare mass of C2H60 = 46.07 golms) No. of moles = 72.2 - = 1.567 mola 1 16.07 volume in litre = 2.22L inlarity = 1.567 mol = 0.7059 mol/L 2.22 L Molarity = 10.766 mol/L cansmer

part oi " 11.29 mg k in 108.6 ml of solution. Molarity = No. of moles of salute volume of solution intitre No. of moles = wt. of salute in gm Molar mals of solute wt of Solute = 11.2 g mg. = 11: 29 x 10-3 gem KI molar mals = 166gnlms I No. of moles = 11.28810-3 - 9m 166 gr/mol 1129 X 10 gm 166 gm/mol 6.8012 X 10 -5 mole - volume = 108.6ml = 0.1086 litre - Molarity = 6. 8012 x10-5 Kiomis I 0.1086 litre = 62.626 X10-5 mollitre 6.263x10-4 molllitre cansuur