When a piece of paper is held at an angle so that the plane of the paper makes an angle 61 ° with the electric field, the electric flux through it is 232 N.m2/C. Find the electric flux when the paper is turned so that the plane of the paper is perpendicular to the electric field. Express your answer in units of N.m2/C with one decimal place. Note that your answer should be positive.
Electric flux at an angle
,
=
EA cos
Where E is the electric field and A is the area of paper.
Given that when
= 61 degrees,
= 232
Nm2/C
232 = EA cos(61)
EA = 232/cos(61)
= 478.54 Nm2/C
When the paper is held perpendicular to the direction of
electric field, angle between A and E becomes zero degree.
m = EA
cos(0)
= EA
= 478.5 Nm2/C
When a piece of paper is held at an angle so that the plane of the...
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