Question

python

1. Write a function called has_odd_even that takes three integers as parameters and that returns True if there is at least one odd and at least one even among the three numbers and that returns False otherwise. Below are some sample calls and the appropriate value to return.

Function call	Value returned
has_odd_even(2, 4, 6)	False
has_odd_even(2, 3, 4)	True
has_odd_even(12, 4, 17)	True
has_odd_even(5, 17, 4)	True
has_odd_even(14, 7, 5)	True
has_odd_even(5, 4, 2)	True
has_odd_even(13, 20, 91)	True
has_odd_even(7, 19, 5)	False

You may assume that all three integers passed to your function are greater than or equal to 0.

Answer 1

def has_odd_even(n1, n2, n3):
    return (n1 % 2 == 0 or n2 % 2 == 0 or n3 % 2 == 0) and (n1 % 2 == 1 or n2 % 2 == 1 or n3 % 2 == 1)


# Testing the function here. ignore/remove the code below if not required
print(has_odd_even(2, 4, 6))
print(has_odd_even(2, 3, 4))
print(has_odd_even(12, 4, 17))
print(has_odd_even(5, 17, 4))
print(has_odd_even(14, 7, 5))
print(has_odd_even(5, 4, 2))
print(has_odd_even(13, 20, 91))
print(has_odd_even(7, 19, 5))