A nozzle of inner radius 1.04 mm is connected to a hose of inner radius 9.35...

Question

Question

A nozzle of inner radius 1.04 mm is connected to a hose of inner radius 9.35 mm. The nozzle shoots out water moving at 25.0 m/s.

What is the mass flow rate?

science physics

Answer 1

Answer #1

Mass flow rate = mass of liquid flowing / time

= volume × density / time

= area × length × density / time

= area × speed × density

= × (1.04×10^-3)² × 25 × 1000

= (22/7) × 1.0816 × 25 × 10^-3

= 84.98 × 10^-3 kg/s

[ Note - Volume flow rate = area × speed

= 84.98 × 10^-6 m³/s ]

Answer 2

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