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Imagine that a couple is planning to have children. The Male is heterozygous for tongue rolling...

Imagine that a couple is planning to have children. The Male is heterozygous for tongue rolling and homozygous dominant for unattached earlobes. The female is homozygous recessive for tongue rolling and heterozygous for unattached earlobes. The ability to roll ones tongue is dominant [R] over the non rolling tongue [r]. Unattached earlobes [U] are dominant over attached earlobes [u]. complete a Punnett square for this cross and record the probabilities for genotypes and phenotypes of the offspring as ratios.

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Answer #1

The genotype of male- RrUU

The genotype of female- rrUu

Now crossing,

RrUU X rrUu

Gametes- RU RU rU rU

rU ru rU ru

RU RU rU rU
rU RrUU RrUU rrUU rrUU
rU RrUU RrUU rrUU rrUU
ru RrUu RrUu rrUu rrUu
ru RrUu RrUu rrUu rrUu

RrUU : 4

rrUU : 4

RrUu : 4

rrUu : 4

The genotypic ratio will be 4:4:4:4 or 1:1:1:1. Now the phenotypic ratio will be again 8:8 or 1:1 for Rolling Tongue and unattached earlobes and for Non-rolling tongues and attached earlobes

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