How many grams of sucrose (C12H22O11) are dissolved in 500 mL of a 100 mM solution?
Answer:
17.1148 grams of sucrose are dissolved in 500 mL of a 100 mM solution.
Explanation:
First we need to calculate the number of moles sucrose in the given solution then from that we can calculate the grams of sucrose.
Calculation of moles of sucrose.
100 mM means 100 miliMolar solution.
Which means 100 milimoles of sucrose per 1 liter of solution.
100 milimoles per liter = 0.1 moles per liter. (100 milimol = 0.1 mol)
That is, 0.1 moles of sucrose present in 1 liter of solution.
The concentration of the sucrose solution is 0.1 mol/L
Now we can calculate the number of moles from following equation,
[ Number moles of sucrose = concentration of solution ÷ volume of solution ]
Given solution has a volume of 500 mL = 0.5 L (given)
Concentration = 0.1 mol/L
Now put these values in the equation,
Number of moles of sucrose = 0.1 mol/L × 0.5 L
Number of moles of sucrose = 0.05 mol
Now, we can calculate the mass(in gram) of sucrose from number of moles using following equation.
Mass = number of moles × molecular weight
Number of moles = 0.05 mol (we determined it earlier)
Molecular weight = 342.2965 g/mol
Now put these values in the equation to get the answer,
Mass = 0.05 mol × 341.2965 g/mol
Mass = 17.1148 g.
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