1) Show the calculation of the heat absorbed by water in calories of Food Item A and B?
Food Item A: Marshmallows:
Mass of water (g): 99.883 g
Initial Mass of Food (g) (fuel+paper clip): 8.473 g
Initial Temperature of Water (C): 22.5 C
Final Temperature of Water (C): 26.7 C
Change in Temperature (C): 4.2 C
FInal Mass of Food (g): 7.637 g
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Food Item B: Cheetos:
Mass of water (g): 110.214 g
Initial Mass of Food (g) (fuel+paper clip): 3.493 g
Initial Temperature of Water (C): 22.1 C
Final Temperature of Water (C): 35.1 C
Change in Temperature (C): 13.0 C
FInal Mass of Food (g): 2.448 g
1) Show the calculation of the heat absorbed by water in calories of Food Item A...
Data Table 2: Caloric Calculations Walnut Marshmallow (Jumbo) Tortilla Chip Food Item Description: Mass of food, cup, and clip - initial (g) 5.98g 9.59 5.87 Mass of food, 5.49g 9.39 3.96 .49g .20g 1.91g took about little over a minute to catch on fire, small fi faster to catch fire, small flame but once put on paper fast to catch fire, big flame, and stayed on fire longer cup, and clip - final (g) Mass of burned food (g) Observations...
need help with the calculations please.
Paragraph Styles Font Section Please type your name here: Please be am work below. I would recommend wing your work on a piece of arch and then nping any work below. For dimensional analysis, please either insert an equation or we the notation below as an example for the common or 234 Tartan i Word select "Insert and then "Equation Data and Calculations: 1kg Record data for Steps 1-8 here. For steps 9-13, do...
Please help me solve this problem.
(5 points) Table 1: Heat Content of a Snack Food using Calorimetry-see below for calculations PROPERTY TRIAL1 TRIAL 2 TRİAL3 Dorito Snack Used Volume of water (mL) Mass of water (g) Mass of snack (g) Initial temperature (°C) Final temperature (°C) Change in temperature (°C) Heat absorbed by water (cal) 9 ml 个1 19 ml 991 o 346 24.5 33.1 c 8,6 C 2 53 04Ss 24.S C 37.S Heat released by snack (food...
Mass of can (9) 12.65 Mass of can and water (9) 112.24 1.91 Initial mass of food sample (g) Final mass of food sample (9) 0.52 Initial temperature of water (*C) 21.12 Final temperature of water (*C) 23.19 Mass of water (9) Temperature change of water (*C). Do not include a negative sign. Heat gained by water (cal). Do not include a negative sign. Heat gained by water (kcal). Do not include a negative sign. Heat lost by food (cal)....
1. Calculate the heat (expressed in calories) required to heat 115 g of water from 15.4^C to 91.4^C 2. Calculate the heat (in calories) lost by 115 g of water as it cools from 91.4^C to 15.4^C 3. Calculate the temperature change caused by absorption of 3.85 kcal heat by 75.4 g water 4. Calculate the final temperature of 75.4 g of water originally at 12.6^C after it absorbs 3.85 kcal of heat 5. A 23.9 g piece of metal...
Microwave ovens use microwave radiation to heat food. The microwaves are absorbed by the water molecules in the food, which is transferred to other components of the food. As the water becomes hotter, so does the food. Suppose that the microwave radiation has a wavelength of 12.4 cm . How many photons are required to heat 235 mL of coffee from 25.0 ∘C to 62.0 ∘C? Assume that the coffee has the same density, 0.997 g/mL, and specific heat capacity,...
DATE NAME CLASS LED lle Math Calculate the heat gained by the water when the fuels burned Charcoal Q=mx CX AT Q = 50.0 g * 4.186 J/gºC x = _ Joules. Splint Q = 50.0 g * 4.186 J/gºC *_ °C = Joules 3. SEP Use Math Determine how much of the fuel burned (i.e.. the mass of the fuel converted to heat) by subtracting the final mass of the fuel/foil from the initial mass. Charcoal Splint 4. SEP...
a) calculate the temperature change for a 987 gram sample of water that absorbed 6,990 joules of heat. is this endo- or exorthermic? b) how many grams of water when absorbing 12,000 calories will heat from 31.2 degrees c to 99.5 degrees c? c) 69.8 grams of aluminum is heated with 3,900 joules of energy. what will be the temperature change? what would the temperature be if the initial temperature was 25.0 degrees c? the c for aluminum is =...
1050 calories of heat from soybean oil was applied to a 250 g sample of liquid water with an initial temp of 25 degrees C. Determine: a) the final temp of the water, and, b) the change in temperature.
Calculations are based on one trial.
To receive full credit, you must SHOW ALL OF YOUR WORK. Answers that do not have complete work shown will be marked as incorrect. Workstation : Part A: Specific Heat of an unknown Metal 1. Unknown number 1326 18.09 8.37 2. Mass of unknown metal 9 3. Mass of empty calorimeter 9 Trial 1 Trial 2 Mass of calorimeter + water 45.23 g g Mass water 36.86 g g Initial Temperature of metal 100...