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A circuit consists of a series combination of 6.00-kΩ and 5.00-kΩ resistors connected across a 50.0-V...

A circuit consists of a series combination of 6.00-kΩ and 5.00-kΩ resistors connected across a 50.0-V battery having negligible internal resistance. You want to measure the true potential difference (that is, the potential difference without the meter present) across the 5.00-kΩresistor using a voltmeter having an internal resistance of 10.0 kΩ.

You may want to review (Pages 858 - 862) .

For related problemsolving tips and strategies, you may want to view a Video Solution of Measuring resistance.

Part A

What potential difference does the voltmeter measure across the 5.00-kΩ resistor?

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Part B

What is the true potential difference across this resistor when the meter is not present?

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Part C

By what percentage is the voltmeter reading in error from the true potential difference?

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Answer #1

application of ohm law

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