Majesty Video Production Inc. wants the mean length of its advertisements to be 30 seconds. Assume...
Majesty Video Production Inc. wants the mean length of its advertisements to be 30 seconds. Assume the distribution of ad length follows the normal distribution with a population standard deviation of 2 seconds. Suppose we select a sample of 18 ads produced by Majesty.
-
What can we say about the shape of the distribution of the sample mean time?
-
What is the standard error of the mean time? (Round your answer to 2 decimal places.)
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What percent of the sample means will be greater than 31.25 seconds? (Round your z values and final answer to 2 decimal places.)
Homework Answers
a) The shape of the distribution will be normal because the original population is having normal distribution.
b) Standard error = 
=
0.47
c) P(Mean > 31.25)
= P(z > 2.65)
= 0.0040
= 0.00 [Rounded off to 2 decimals]
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