If a particular ore contains 56.1 % calcium phosphate, what minimum mass of the ore must...

Question

Question

If a particular ore contains 56.1 % calcium phosphate, what minimum mass of the ore must be processed to obtain 1.00 kg of phosphorus?

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Answer 1

Answer #1

Molar mass of calcium phosphate = 310.18 g/mol

Molar mass of phosphorous = 30.99 g/mol

30.99 g phosphorous is present in 310.18g calcium phosphate

1000 g phosphorous is present in 310.18×1000/30.99 g calcium phosphate

= 10009.04 g calcium phosphate

56.1 g calcium phosphate is present in 100 g ore

10009.04 g calcium phosphate is present in

100×10009.04/56.1 g ore

= 17841.42 g ore

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Answer 2

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