Question

*****THIS IS FOR MY PYTHON CLASS. PLEASE HELP*****

{
 "cells": [
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "#### CS 497 Lab 1\n",
    "\n",
    "\n",
    "### Instructions\n",
    "0. Rename this file username_lab1.  **Not literally, yourName_lab1 (technically correct, the best kind of correct!) but use your BU ID to fill in yourName.**  If I was submitting this lab, it would be called dbrennan_lab1.\n",
    "1. Read all instructions carefully, ask questions if anything is confusing.  \n",
    "2. Fill in the code/text blocks to answer each question.\n",
    "3. Do *not* change any of the existing code provided.  The code is specifically there to help you!\n",
    "4. Run the entire notebook *before* submitting it on Sakai to make sure that the code actually runs without errors.\n",
    "5. **Important**: Any question for which your code fails to run will receive 0 points.\n",
    "6. Have fun!\n",
    "7. Extra credit (if applicable) will only be granted if this lab is turned in before the end of class\n",
    "8. **Do not import any packages!**  Any packages available to you are designed to be used from their import statement down.  \n",
    "\n",
    "Example:  Problem 1 doesn't have any import statements.  Problem 2 imports one package called \"A\".  Problem 3 imports one package called \"B\".  You may not use \"A\" or \"B\" for problem 1, you may not use \"B\" for problem 2 and you may use both for problem 3.  If you were to restart and rerun all cells in your notebook you would not be able to use a package prior to importing it so it logically makes sense as well!\n"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "# Question 1 30 points\n",
    "\n",
    "Please sum up the numbers from 1 to N where, you choose to set N below.  The formula for the summation is provided, check your work!\n",
    "\n",
    "**This would look like $\\sum_{i=1}^ni=\\frac{(n+1)(n)}{2}$ if we were in a math class.**"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 1,
   "metadata": {},
   "outputs": [],
   "source": [
    "##Your code below, you may change n to any value\n",
    "n = 1"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "# Question 2 30 points\n",
    "\n",
    "It's quite cold outside.  Don't go outside.  If you've always wondered how wind chill is calculated, today is your lucky day!\n",
    "\n",
    "The formula for calculating wind chill in T degrees Celsius and v km/hour is given below:\n",
    "\n",
    "$WC=13.12+.6215t-11.37[v^{\\frac{16}{100}}]+.3965t[v^{\\frac{16}{100}}]$\n",
    "\n",
    "Implement the above formula carefully, the wind chill at v=21, and T=-27 yields a wind chill of -39.6 (remember these are metric measurements!) \n",
    "\n",
    "0 deg C and 30 km/h yields a WC of -6.5"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": [
    "##Your code below, but change the values of T/v to test both pairs \n",
    "t = -27\n",
    "v = 21\n",
    "\n"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "# Question 3 40 points + 5 points EC\n",
    "\n",
    "You will be building your own quadratic equation solver!  Since we aren't importing the math library we will rely on the ** exponent we saw in class on Monday.  \n",
    "\n",
    "The quadratic equation $ax^2+bx+c=0$ can be solved by root 1 is $\\frac{-b-\\sqrt{b^2-4ac}}{2a}$ and root 2 is $\\frac{-b+\\sqrt{b^2-4ac}}{2a}$\n",
    "\n",
    "Now of course when the inside of the square root is less than zero we work with imaginary numbers.  For extra credit, you will find a way to print out those imaginary roots.  I'll leave how you handle that up to you.\n",
    "\n",
    "For normal credit, merely print out the two roots (with the provided print statement).\n",
    "\n",
    "a=2,b=5,c=-3 should yield roots of -3 and .5"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 7,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "Root 1 is: 0\n",
      "Root 2 is: 0\n"
     ]
    }
   ],
   "source": [
    "root1=0\n",
    "root2=0\n",
    "\n",
    "a=2\n",
    "b=5\n",
    "c=-3\n",
    "##Write your code below, modify root1 and root2 accordingly\n",
    "\n",
    "\n",
    "\n",
    "print(\"Root 1 is:\",root1)\n",
    "print(\"Root 2 is:\",root2)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": []
  }
 ],
 "metadata": {
  "kernelspec": {
   "display_name": "Python 3",
   "language": "python",
   "name": "python3"
  },
  "language_info": {
   "codemirror_mode": {
    "name": "ipython",
    "version": 3
   },
   "file_extension": ".py",
   "mimetype": "text/x-python",
   "name": "python",
   "nbconvert_exporter": "python",
   "pygments_lexer": "ipython3",
   "version": "3.7.0"
  }
 },
 "nbformat": 4,
 "nbformat_minor": 2
}

Answer 1

Solution:

homework.ipynb

{
"cells": [
{
"cell_type": "markdown",
"metadata": {
"collapsed": false
},
"source": [
"#### CS 497 Lab 1\n",
"\n",
"\n",
"### Instructions\n",
"0. Rename this file username_lab1. **Not literally, yourName_lab1 (technically correct, the best kind of correct!) but use your BU ID to fill in yourName.** If I was submitting this lab, it would be called dbrennan_lab1.\n",
"1. Read all instructions carefully, ask questions if anything is confusing. \n",
"2. Fill in the code/text blocks to answer each question.\n",
"3. Do *not* change any of the existing code provided. The code is specifically there to help you!\n",
"4. Run the entire notebook *before* submitting it on Sakai to make sure that the code actually runs without errors.\n",
"5. **Important**: Any question for which your code fails to run will receive 0 points.\n",
"6. Have fun!\n",
"7. Extra credit (if applicable) will only be granted if this lab is turned in before the end of class\n",
"8. **Do not import any packages!** Any packages available to you are designed to be used from their import statement down. \n",
"\n",
"Example: Problem 1 doesn't have any import statements. Problem 2 imports one package called \"A\". Problem 3 imports one package called \"B\". You may not use \"A\" or \"B\" for problem 1, you may not use \"B\" for problem 2 and you may use both for problem 3. If you were to restart and rerun all cells in your notebook you would not be able to use a package prior to importing it so it logically makes sense as well!\n"
]
},
{
"cell_type": "markdown",
"metadata": {
"collapsed": false
},
"source": [
"# Question 1 30 points\n",
"\n",
"Please sum up the numbers from 1 to N where, you choose to set N below. The formula for the summation is provided, check your work!\n",
"\n",
"**This would look like $\\sum_{i=1}^ni=\\frac{(n+1)(n)}{2}$ if we were in a math class.**"
]
},
{
"cell_type": "code",
"execution_count": 2,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"45.0\n"
]
}
],
"source": [
"##Your code below, you may change n to any value\n",
"n = 10\n",
"for i in range(n):\n",
" result = (i+1)*(i)/2\n",
"print(result)"
]
},
{
"cell_type": "markdown",
"metadata": {
"collapsed": false
},
"source": [
"# Question 2 30 points\n",
"\n",
"It's quite cold outside. Don't go outside. If you've always wondered how wind chill is calculated, today is your lucky day!\n",
"\n",
"The formula for calculating wind chill in T degrees Celsius and v km/hour is given below:\n",
"\n",
"$WC=13.12+.6215t-11.37[v^{\\frac{16}{100}}]+.3965t[v^{\\frac{16}{100}}]$\n",
"\n",
"Implement the above formula carefully, the wind chill at v=21, and T=-27 yields a wind chill of -39.6 (remember these are metric measurements!) \n",
"\n",
"0 deg C and 30 km/h yields a WC of -6.5"
]
},
{
"cell_type": "code",
"execution_count": 4,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"-39.59119651700358\n",
"-6.472951590454416\n"
]
}
],
"source": [
"##Your code below, but change the values of T/v to test both pairs \n",
"t = -27\n",
"v = 21\n",
"\n",
"wc = 13.12 + 0.6215*(t) - 11.37 * (v**0.16) + 0.3965*(t)*(v**0.16)\n",
"\n",
"print(wc)\n",
"\n",
"t = 0\n",
"v = 30\n",
"\n",
"wc = 13.12 + 0.6215*(t) - 11.37 * (v**0.16) + 0.3965*(t)*(v**0.16)\n",
"\n",
"print(wc)\n",
"\n",
"\n"
]
},
{
"cell_type": "markdown",
"metadata": {
"collapsed": false
},
"source": [
"# Question 3 40 points + 5 points EC\n",
"\n",
"You will be building your own quadratic equation solver! Since we aren't importing the math library we will rely on the ** exponent we saw in class on Monday. \n",
"\n",
"The quadratic equation $ax^2+bx+c=0$ can be solved by root 1 is $\\frac{-b-\\sqrt{b^2-4ac}}{2a}$ and root 2 is $\\frac{-b+\\sqrt{b^2-4ac}}{2a}$\n",
"\n",
"Now of course when the inside of the square root is less than zero we work with imaginary numbers. For extra credit, you will find a way to print out those imaginary roots. I'll leave how you handle that up to you.\n",
"\n",
"For normal credit, merely print out the two roots (with the provided print statement).\n",
"\n",
"a=2,b=5,c=-3 should yield roots of -3 and .5"
]
},
{
"cell_type": "code",
"execution_count": 5,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"Root 1 is: -3.0\n",
"Root 2 is: 0.5\n"
]
}
],
"source": [
"root1=0\n",
"root2=0\n",
"\n",
"a=2\n",
"b=5\n",
"c=-3\n",
"##Write your code below, modify root1 and root2 accordingly\n",
"\n",
"root1 = (-b - (b**2 - 4*a*c)**0.5)/(2*a)\n",
"root2 = (-b + (b**2 - 4*a*c)**0.5)/(2*a)\n",
"print(\"Root 1 is:\",root1)\n",
"print(\"Root 2 is:\",root2)"
]
},
{
"cell_type": "code",
"execution_count": 0,
"metadata": {
"collapsed": false
},
"outputs": [
],
"source": [
]
}
],
"metadata": {
"kernelspec": {
"display_name": "Python 3 (Ubuntu Linux)",
"language": "python",
"name": "python3"
},
"language_info": {
"codemirror_mode": {
"name": "ipython",
"version": 3
},
"file_extension": ".py",
"mimetype": "text/x-python",
"name": "python",
"nbconvert_exporter": "python",
"pygments_lexer": "ipython3",
"version": "3.6.7"
}
},
"nbformat": 4,
"nbformat_minor": 0
}

Simple way to get your file is here:

https://cocalc.com/share/6521eafd-b409-414d-8758-57c03a19c7e3/2019-02-01-230947/homework.ipynb?viewer=share

Just go to this link you will find your homework there.

Note: If you have any doubt then please do comment below. I will be glad to help you out thanks. Just replace this json provided with your json file and name it homework.ipynb and open it in jupyter notebook . It should work like a charm.