Question

I need help writing the test case in C++ code 
can you help? This is apart of my professors pseudo code for the project.

// TEST CASE 1
//
// DESCRIPTION

// Coefficients a and c are > 0 and b < 0 so the equation should be output as:
//
//     p(x) = 122.50000x^2 - 6.70000x + 3.00000 = 0
//

// where we note that the operator printed before b is subtraction and we
 actually output -b rather than b. Also

// this equation has complex roots so the program should output two complex
 numbers which are complex conjugates

//
// INPUT DATA
//a=122.5 b=-6.7 c=3
//
// EXPECTED OUTPUT
// The equation p(x) = 122.50000x^2 - 6.70000x + 3.00000 = 0 has two complex

 roots: root1 = 0.02735 + 0.15408i
// and root2 = 0.02735 - 0.15408i
//
// ACTUAL OUTPUT:

// The equation p(x) = 122.50000x^2 - 6.70000x + 3.00000 = 0 has two complex
 roots: root1 = 0.02735 + 0.15408i

// and root2 = 0.02735 - 0.15408i
//

Answer 1

C++ program for Test Case 1

#include <iostream>
#include <cmath> // including cmath library to call sqrt() function

using namespace std;

int main()
{
double a, b, c, discriminant, imaginary, real; // Variable decleration
// sequence of cout and cin to get the input data
cout<< "INPUT DATA\na=";
cin >> a;
cout << "b=";
cin >> b;
cout << "c=";
cin >> c;
// Computing the discriminant, discriminant< 0 so multiply with -1 to compute squart
discriminant = b*b-4*a*c;
imaginary = sqrt(discriminant*-1)/2/a; // Computing the imaginary part of the root
real = -1*b/2/a; // Computing the real part of the root
// Printing the required informations to the output
printf("The equation p(x) = %0.5fx^2 - %0.5fx + %0.5f = 0 has two complex roots:",a,-1*b,c);
printf("root1 = %0.5f + %0.5fi\n root2 = %0.5f - %0.5fi \n", real, imaginary, real, imaginary);
}

Screen shot of the code

SAMPLE OUTPUT OF THE CODE

REMARK

The program is compiled using g++ in Linux system.