The pKa of the ammonium ion is 9.25. At what pH is ammonia 35 % ionized?
The fraction of un-ionized ammonia is given by
f = 1/(10^(pKa-pH) + 1)
0.65 = 1/[10^(9.25 - pH) + 1]
10^(9.25 - pH) + 1 = 1/0.65
pH = 9.52 answer
The pKa of the ammonium ion is 9.25. At what pH is ammonia 35 % ionized?
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