Question

A ball is thrown from an initial height of 2.2 meters with an initial angle of 32 degrees and stays in the air 1.2 seconds. How far (horizontally) does it go?

Answer 1

The equation of motion of the projectile is given by

So, the time at which the projectile will touch the ground is obtained by solving the y = 0, which is basically a quadratic equation in terms of t and is given by

And as h, t and are given, so, we calculate the speed of the projectile from the above formula as
  
And so, the horizontal distance travelled at that time t with the above speed u is given by
  
Now putting the given values,
  
we get the magnitude of the horizontal distance travelled