Suppose you have a page size of 4096 bytes and a process size of 93,425 bytes....
- Suppose you have a page size of 4096 bytes and a process size
of 93,425 bytes.
- How many pages would the process need?
- What would be the internal fragmentation of the process?
- Suppose you have a page size of 2048 bytes and a process size
of 501,345 bytes.
- How many pages would the process need?
- What would be the internal fragmentation of the process?
Homework Answers
Number of pages = Process size/ Page Size
and
Internal fragmentation is the amount of spae left unused in the last page of the process. It can be identified by finding remainder of Process size/ Page Size .
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Suppose you have a page size of 4096 bytes and a process size
of 93,425 bytes....
I need help with this problem.I am currenlty struggelling with it. Consider a computer system using paging, where the address space of every process has a size of C = 2c bytes and the page size is S...
I need help with this problem.I am currenlty struggelling
with it.
Consider a computer system using paging, where the address space
of every process has a size of C = 2c bytes and the page size is S
= 2s bytes. Each entry in the page table uses E bytes.
Calculate the number of pages of a process, and the size of a
page table (in bytes).
Assume that the space wasted by a process in main memory is
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I need help with this problem.I am currenlty struggelling
with it.
Consider a computer system using paging, where the address space
of every process has a size of C = 2c bytes and the page size is S
= 2s bytes. Each entry in the page table uses E bytes.
Calculate the number of pages of a process, and the size of a
page table (in bytes).
Assume that the space wasted by a process in main memory is
defined...
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