Consider a simple paging system with the following parameters: 232 bytes of physical memory; page size...

Question

Question

Consider a simple paging system with the following parameters: 2³² bytes of physical memory; page size of 2¹⁰ bytes; 2¹⁶ pages of logical address space.
1. How many bits are in a logical address?
2. How many bytes in a frame?
3. How many bits in the physical address specify the frame?
4. How many entries in the page table?

engineering Computer-Science

Answer 1

Answer #1

given the various parameter

2³² bytes of physical memory

page size of 2¹⁰ bytes

2¹⁶ pages of logical address space

a) no. of bits are in logical address = 10+16=26 bits

b) Bytes in a frame= 2^10 byte

c) no. of bits in the physical address specify the frame =32-10=22

d) no. of entries in the page table = 2^16=65536 entries

:_

Answer 2

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