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Albinism (lack of pigmentation in the skin) in the mouse is due to a homozygous autosomal...

Albinism (lack of pigmentation in the skin) in the mouse is due to a homozygous autosomal recessive allele (a) whereas normal pigmentation is the consequence of a dominant allele (A). If an albino mouse, it crosses with a female of normal skin but carrier of the recessive allele (Aa). What is the genotype of F1? If a non-albino individual of F1 is backcrossed with the albino parent, what proportion of the new F2 mice will be albino?
Develop Punnet charts and justification

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Answer #1

Answer. Normal skin female genotype = Aa.

Male genotype = aa

F1 generation,

a
A Aa
a aa

Half will be carrier and half will be albino.

Then if non albino from F1 back crossed with albino parent

Non albino F1 generation genotype = Aa.

Albino genotype =aa

Then punnett square, F2 generation

a
A Aa
a aa

Then half will be albino and half will be non albino but carrier.

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