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A car is traveling up a hill that is inclined at an angle θ above the...

A car is traveling up a hill that is inclined at an angle θ above the horizontal. Determine the ratio of the magnitude of the normal force to the weight of the car when (a)  θ = 19o and (b)  θ = 31o.

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Answer #1

Well, the weight acts vertically downward and is given by (mg)
The normal force is given by [mg cos(theta)]

So the ratio of normal to weight is
=m g cos(theta) / mg

= cos (theta)

a) Ratio = cos 19

= 0.945

b) Ratio = cos 31

= 0.857

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