1.22 [1pt] Consider a sheet of paper with a thickness of 0.1 mm and a dielectric...
1.22 [1pt] Consider a sheet of paper with a thickness of 0.1 mm and a dielectric constant of 3. Suppose we would like to make a 1 F capacitor using this sheet as a spacer between two metallic plates. What should be the area of the sheet?
1.22 ANSWER
Suppose we took a 1 F capacitor from problem 1.22 and attached a 1V battery to it. After the charging was complete the battery was disconnected.
1.23 [1pt] What is the charge on the capacitor?
1.23 ANSWER
1.24 [1pt] How much work did the battery produce?
1.24 ANSWER
1.25 [1pt] What is the total energy of the capacitor after charging?
1.25 ANSWER
Homework Answers
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1.22 [1pt] Consider a sheet of paper with a thickness of 0.1 mm
and a dielectric...
4. A dielectric-filled capacitor is directly connected to a 12.0-V battery until it is fully charged....
4. A dielectric-filled capacitor is directly connected to a 12.0-V battery until it is fully charged. Then the capacitor is disconnected from the battery and, once disconnected, the dielectrie is removed so that air fills the capacitor instead. The dielectric used is pyrex glass, whose dielectric constant is 5.6, while the dielectric constant of air is 1.0059. (a) Determine the voltage across the capacitor plates after the dielectric is removed. (b) With the dielectric removed, the capacitor is discharged by...
Chapter 18-Homework Practice Problem 18.10 Now let's examine the effects of placing a dieletric film Part...
Chapter 18-Homework Practice Problem 18.10 Now let's examine the effects of placing a dieletric film Part C- Practice Problem: between the plates of a capacitor. The plates of an air led parallel-plate capacitor each harve area 2.00 x 10 em and are 1.00 em apart. The capacilor is connected to a power difference of V6 = 3.00 kV The capacitor is then disconnected from the power supply without any charge being lost from its plates. After the capacitor has been...
4.2 Dielectric materials used in the manufacture of capacitors are characterized bv conductivities that are small...
4.2 Dielectric materials used in the manufacture of capacitors are characterized bv conductivities that are small but not zero. Therefore, a charged capacitor loses its charge by slowly leaking across the dielectric. Consider a parallel-plate capacitor with plate spacing d and area A. The volume between the plates is filled with material having dielectric constant K but also with finite resistivity ρ a. What is the capacitance C, in terms of eo, K, A and d? b. What is the...
Question 7 (3 Points) This assignment is set up for sequential assessment. Complete each question and...
Question 7 (3 Points) This assignment is set up for sequential assessment. Complete each question and submit the answer before moving on to the next question. Correct answers for each question will be made available once the maximum number of attempts have been made for each submission. Capacitance 3 - Mixed C=K Formulas: Capacitors with dielectrics (with dielectric) (without dielectrie) EA d d E = EA AV = Ed For ALL capacitors Q=CAV + -Q+Q2 -Q2 +Q3 -Q3 Step 1...
Consider a monoatomic ideal gas undergoing the following cycle: starting point (a), pressure increases at a...
Consider a monoatomic ideal gas undergoing the following cycle: starting point (a), pressure increases at a constant volume reaching point (b), then the gas expands adiabatically until pressure reaches the initial value (point c), and then the gas is compressed at a constant pressure until the volume reaches the initial value back to point (a). The amount of gas is 1 mole. Monoatomic gas means it has only 3 degrees of freedom and the adiabatic constant gamma is 5/3. Sketch...
Consider a cylindrical capacitor like that shown in Fig. 24.6. Let d = rb − ra...
Consider a cylindrical capacitor like that shown in Fig. 24.6. Let d = rb − ra be the spacing between the inner and outer conductors. (a) Let the radii of the two conductors be only slightly different, so that d << ra. Show that the result derived in Example 24.4 (Section 24.1) for the capacitance of a cylindrical capacitor then reduces to Eq. (24.2), the equation for the capacitance of a parallel-plate capacitor, with A being the surface area of...
4. A dielectric-filled capacitor is directly connected to a 12.0-V battery until it is fully charged. Then the capacitor is disconnected from the battery and, once disconnected, the dielectrie is removed so that air fills the capacitor instead. The dielectric used is pyrex glass, whose dielectric constant is 5.6, while the dielectric constant of air is 1.0059. (a) Determine the voltage across the capacitor plates after the dielectric is removed. (b) With the dielectric removed, the capacitor is discharged by...
Chapter 18-Homework Practice Problem 18.10 Now let's examine the effects of placing a dieletric film Part C- Practice Problem: between the plates of a capacitor. The plates of an air led parallel-plate capacitor each harve area 2.00 x 10 em and are 1.00 em apart. The capacilor is connected to a power difference of V6 = 3.00 kV The capacitor is then disconnected from the power supply without any charge being lost from its plates. After the capacitor has been...
4.2 Dielectric materials used in the manufacture of capacitors are characterized bv conductivities that are small but not zero. Therefore, a charged capacitor loses its charge by slowly leaking across the dielectric. Consider a parallel-plate capacitor with plate spacing d and area A. The volume between the plates is filled with material having dielectric constant K but also with finite resistivity ρ a. What is the capacitance C, in terms of eo, K, A and d? b. What is the...
Question 7 (3 Points) This assignment is set up for sequential assessment. Complete each question and submit the answer before moving on to the next question. Correct answers for each question will be made available once the maximum number of attempts have been made for each submission. Capacitance 3 - Mixed C=K Formulas: Capacitors with dielectrics (with dielectric) (without dielectrie) EA d d E = EA AV = Ed For ALL capacitors Q=CAV + -Q+Q2 -Q2 +Q3 -Q3 Step 1...
Consider a cylindrical capacitor like that shown in Fig. 24.6. Let d = rb − ra be the spacing between the inner and outer conductors. (a) Let the radii of the two conductors be only slightly different, so that d << ra. Show that the result derived in Example 24.4 (Section 24.1) for the capacitance of a cylindrical capacitor then reduces to Eq. (24.2), the equation for the capacitance of a parallel-plate capacitor, with A being the surface area of...
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