Help me please :) Consider two parallel plate capacitors. The plates on Capacitor B have twice...
Help me please :)
Consider two parallel plate capacitors. The plates on Capacitor B have twice the area as the plates on Capacitor A, but the plates in both Capacitor B and Capacitor A are separated by 100~ \mu \text{m}100 μm of air. If Capacitor A has a capacitance of C_A = 30.4 nFCA=30.4nF, what is the capacitance of Capacitor B?
Show work please!
Homework Answers
Capacitance is C=e0*A/d.
Here e0 is constant. So, Ca=e0*A/d and Cb= e0*2A/d
So, Cb= (e0*A/d) *2 = 60.8nF
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