A random sample of size n=613 from a population whose parameter is p=0.43.
Solution
Given that,
p = 0.43
1 - p = 1-0.43=0.57
n = 613
mean =
= p =0.43
standard deviation =
=
[p
( 1 - p ) / n] =
[(0.43*0.57) / 613 ] = 0.02
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