Two short-eared pigs are mated. Of the resulting the progeny three have no ears, seven have...
Two short-eared pigs are mated. Of the resulting the progeny three have no ears, seven have short ears, and four have long ears. Explain these results by diagramming the cross.
Homework Answers
Given that, mating parents are both short eared, and they produce offspring which comprise 3 without ears, 7 with short ears and 4 with long ears.
In the progeny, ratio of no ear to short ear to long ears can be found by dividing each by 3 (value for phenotype with least number ):
3/3 = 1
7/3= 2.33
4/3= 1.33
It is approximately 1:2:1
This ratio corresponds to incomplete dominance, in which none of the allele is dominant when they are present together. This can be explained as follows:
Let the allele for no ear be "a" and allele for long ears be "A". An individual has two alleles for a gene, and for ear length we can have three possibilities: aa individuals, Aa individuals and AA individuals.
aa types will have no ears, AA types will have long ears.
But, Aa individuals will have a blend of the two alleles, A and a , and phenotype will be short ears.
Following the question, cross can be shown as:
Short ear (Aa) x Short ear (Aa) ( parents)
| A | a | |
| A | AA (long ear) | Aa (short ear ) |
| a | Aa (short ear) | aa (no ear) |
Thus, we can see that Aa, Aa and aa will be in the ratio 1:2:1.
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