As the lab instructor for Cell Biology, you need to make a solution of DCMU, an...
As the lab instructor for Cell Biology, you need to make a solution of DCMU, an inhibitor of photosynthetic electron transport. You want a final concentration of 2x10-4M in a final volume of 2 ml, and this needs to be achieved using a single 10 ul transfer using the micropipette. How much DCMU should you weigh out to dissolve in 20ml of alcohol? The MW of DCMU is 400g/mole.
Homework Answers
Answer:
Stock= ?
Required=2 x 10^-4 M
Volume required= 2000 uL
Stock volume= 10uL
We can use
C1V1= C2V2
(stock) (required)
C1=C2V2/V1
C1=(2 x 10^-4x 2000 uL)/ 10uL
C1=0.04M
How much DCMU should you weigh out to dissolve in 20ml of alcohol? The MW of DCMU is 400g/mole.
We need to prepare a stock of 0.04M
Weight in grams= M x MW x Vol L
=0.04 M x 400 g/mole x 0.02L
=0.32g
You should you weigh out 0.32g of DCMU in 20mL of alcohol
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