Question

Evaluate each of the following C++ expressions. (a) i1 + (i2 * i3) (b) i1 * (i2 + i3) (c) i1 / (i2 + i3) (d) i1 / i2 + i3 (e) 3 + 4 + 5 / 3 (f) (3 + 4 + 5) / 3 (g) d1 + (d2 * d3) (h) d1 + d2 * d3 (i) d1 / d2 - d3 (j) d1 / (d2 - d3) (k) d1 + d2 + d3 / 3 (l) (d1 + d2 + d3) / 3 (m) d1 + d2 + (d3 / 3) (n) 3 * (d1 + d2) * (d1 - d3)

Answer 1

Solution:

For the evaluation of expressions you didn't provide the values for variables like i1, i2, i3 etc. So I am assuming the values and evaluating expressions using them. Evaluation of these expressions is based on the precedence and associativity of the operators.

Let

int i1 = 2, i2 = 5, i3 = -3;
double d1 = 2.0, d2 = 5.0, d3 = -0.5;

Now come to the question,

(a) i1 + (i2 * i3) = -13

2 + (5 * -3) = 2 - 15 = -13

(b) i1 * (i2 + i3) = 4

2 * (5 + -3) = 2 * 2 = 4

(c) i1 / (i2 + i3) = 1

2 / (5 + -3) = 2 / 2 = 1

(d) i1 / i2 + i3 = -3

2 / 5 + -3 = 0 + -3 = -3 (fraction part .4 in 2 / 5 (that is 2 / 5 = 0.4) will be truncated because operation is performed on int datatype so 2 / 5 yields 0)

(e) 3 + 4 + 5 / 3 = 8

3 + 4 + 1 = 8 (fraction part will be truncated because operation is performed on int datatype. 5 / 3 yields 1)

(f) (3 + 4 + 5) / 3 = 4

(3 + 4 + 5) / 3 = 12 / 3 = 4

(g) d1 + (d2 * d3) = -0.5

2.0 + (5.0 * -0.5) = 2.0 - 2.5 = -0.5

(h) d1 + d2 * d3 = -0.5

2.0 + 5.0 * -0.5 = 2.0 - 2.5 = -0.5

(i) d1 / d2 - d3 = 0.9

2.0 / 5.0 - (-0.5) = 0.4 + 0.5 = 0.9

(j) d1 / (d2 - d3) = 0.363636

2.0 / (5.0 - -0.5) = 2.0 / 5.5 = 0.363636

(k) d1 + d2 + d3 / 3 = 6.83333

2.0 + 5.0 + -0.5 / 3 = 7.0 - 0.166667 = 6.83333

(l) (d1 + d2 + d3) / 3 = 2.16667

(2.0 + 5.0 + -0.5) / 3 = 2.16667

(m) d1 + d2 + (d3 / 3) = 6.83333

2.0 + 5.0 + (-0.5 / 3) = 7.0 - 0.166667 = 6.83333

(n) 3 * (d1 + d2) * (d1 - d3) = 52.5

3 * (2.0 + 5.0) * (2.0 - -0.5) = 3 * 7.0 * 2.5 = 52.5

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