Be sure to answer all parts.
Calculate E
|
o |
, E, and ΔG for the following cell
reactions
(a) Mg(s) + Sn2+(aq) ⇌
Mg2+(aq) + Sn(s) where
[Mg2+] = 0.055 M and [Sn2+] = 0.050
M
E
|
|||
| E = V | |||
|
Δ G = kJ |
(b) 3Zn(s) + 2Cr3+(aq) ⇌
3Zn2+(aq) + 2Cr(s) where
[Cr3+] = 0.020 M and [Zn2+] = 0.0095
M
E
|
|||
| E = V | |||
|
Δ G = kJ |
1) Write the half-reactions and their standard reduction potentials to identify reduction (electron gain) , oxidation (electron loss) and the number of transferred electrons:
, 
, 
2) Obtain the standard potential of reaction:


3) Obtain the Gibbs free energy:

4) Obtain E with Nern'st equation, (remember that solids are not written in the equilibrium quotient)

b) Second reaction:
1) Write the half-reactions and their standard reduction potentials to identify reduction (electron gain) , oxidation (electron loss) and the number of transferred electrons:
, 
, 
2) Obtain the standard potential of reaction:


3) Obtain the Gibbs free energy:

4) Obtain E with Nern'st equation, (remember that solids are not written in the equilibrium constant)

Be sure to answer all parts. Calculate E o , E, and ΔG for the following...
(a) Mg(s) + Sn2+(aq) = Mg2+(aq) + Sn(s) where [Mg2+] = 0.035 M and [Sn2+] = 0.040 M E = v AG= kJ (b) 3Zn(s) + 2Cr3+ (aq) = 3Zn2+(aq) + 2Cr(s) where [Cr3+] = 0.040 M and [Zn2+] = 0.0075 M E = AG=
Calculate Eº, E, and AG for the following cell reactions (a) Mg(s) + Sn2+(aq) =Mg2+(aq) + Sn(s) where [Mg2+] = 0.040 M and [Sn2+] = 0.045 M 8° = 2.23 10 E = 2.23 AG=430390 (b) 3Zn(s) + 2Cr3+(aq) = 3Zn2+(aq) + 2Cr(s) where [Cr3+] = 0.040 M and [Zn2+] = 0.0065 M E° = 0.03 E = 0.0671 AG=-0.0389
Calculate Eo , E, and ΔG for the following cell reaction 3Zn(s) + 2Cr3+(aq) ⇌ 3Zn2+(aq) + 2Cr(s) where [Cr3+] = 0.090 M and [Zn2+] = 0.0085 M
1. Which of the following conditions defines a non-spontaneous oxidation-reduction reaction? E° + ΔG° - Keq <1 E° - ΔG° - Keq <1 E° + ΔG°+ Keq >1 E° + ΔG°- Keq >1 E° - ΔG° + Keq <1 2. What information can be obtained from the Figure below? The equivalence point occurs at pH = 7.0 but the pKa is not known from the graph. Both the pOH and the...
Question 5 (1 point) Given: Cr3+(aq) + 3e --> Cr(s); E° = -0.74 V Sn2+(aq) + 2e- --> Sn(s); E° = -0.14 V What is the standard cell potential for the following reaction? 2Cr(s) + 3Sn2+(aq) --> 3Sn(s) + 2Cr3+(aq)? 0-0.60 v 0 +0.60 v O +1.06 V 0 +0.88 V 0-0.88 V
Half-reaction Cr3+ (aq) + 3e- → Cr(s) Fe2+ (aq) + 2e- → Fe (s) Fe3+ (aq) + e- + Fe2+ (s) Sn4+ (aq) + 2e- + Sn2+ (aq) E° (V) -0.74 -0.440 +0.771 +0.154 3Sn** (aq) +2Cr(s) → 2Cr** (aq) +3Sn²+ (aq) 3. What is the cell potential, Ecell, for the reaction above if [Sn] = 1.00 M, [Cr3+1 = 0.0200 M and [Sn2+] = 0.0100 M?
1) Which of the following oxidation-reduction reactions will be spontaneous in the direction written? Select all that apply. Mg2+ (aq) + Be (s) → Mg (s) + Be2+ (aq) Cu2+ (aq) + Zn (s) → Cu (s) + Zn2+ (aq) Hg2+ (aq) + Cu (s) → Hg (l) + Cu2+ (aq) Pb2+ (aq) + Cu (s) → Pb (s) + Cu2+ (aq) Fe2+ (aq) + Pb (s) → Fe (s) + Pb2+ (aq) 2) What is the value (in V)...
A) Use tabulated electrode potentials to calculate ΔG∘ for the reaction. 2K(s)+2H2O(l)→H2(g)+2OH−(aq)+2K+(aq) B) (Refer to the following standard reduction half-cell potentials at 25∘C: VO2+(aq)+Ni2+(aq)2H+(aq)++2e−e−→ →Ni(s)VO2+(aq) +H2O(l)E∘=−0.23V E∘=0.99V) An electrochemical cell is based on these two half-reactions: Oxidation:Reduction:Ni(s)VO2+(aq,0.024M)+2H+(aq,1.4M)+e−→→Ni2+(aq,1.8M)+2e−VO2+(aq,1.8M)+H2O(l) Calculate the cell potential under these nonstandard concentrations. C) Standard reduction half-cell potentials at 25∘C Half-reaction E∘ (V ) Half-reaction E∘ (V ) Au3+(aq)+3e−→Au(s) 1.50 Fe2+(aq)+2e−→Fe(s) − 0.45 Ag+(aq)+e−→Ag(s) 0.80 Cr3+(aq)+e−→Cr2+(aq) − 0.50 Fe3+(aq)+3e−→Fe2+(aq) 0.77 Cr3+(aq)+3e−→Cr(s) − 0.73 Cu+(aq)+e−→Cu(s) 0.52 Zn2+(aq)+2e−→Zn(s) − 0.76...
Consider a voltaic cell where the anode half-reaction is Zn(s) → Zn2+(aq) + 2 e− and the cathode half-reaction is Sn2+(aq) + 2 e– → Sn(s). What is the concentration of Sn2+ if Zn2+ is 2.5 × 10−3 M and the cell emf is 0.660 V? The standard reduction potentials are given below Zn+2(aq) + 2 e− → Zn(s) E∘red == −0.76 V Sn2+(aq) + 2 e– → Sn(s) E∘red −0.136 V
1 pt Calculate the value of E' for each of the following reactions. Decide whether each is product-favored in the direction written Cl2(g) + Mg(s) Mg2+ (aq) + 2 CI" (aq) 1 pt - 1 pt 1 pt You may need to use the following data: Cl(s) +2e + 2 C1" (aq) E' +1.36 V Mg2+ (aq) +2e Mg(s) E-2.37 V 1 pt 1 pt V 1 pt Reaction is 1 pt b. 1 pt Zn(aq) + Mg(s) → Zn(s)...