Question

The Requirement (What you need to do)

You are asked to write a program that takes as input a dollar amount, and then displays the dollar amount in English (similar to how you would write the amount in a check).

Use case (Scenario)

$PrintDollar
Enter the dollar amount:$23.45
It's twenty three and 45/100
Try again(y/n):n
Bye! 

Error handling: You are required to handle the following error inputs. If the input is any of the following case, your program should display appropriate error message, and ask the user to try again.

1. The dollar amount cannot be greater than 9999.99
2. The dollar amount cannot be negative
3. There are at most two decimal digitals in the input
4. Handle non-digit input, such as ten

Note on handling error in input operation

bool wrongInput;
do {
 //attempt to read an int, a char, and another int 
 cin >>dollar >>ch >> cents;
 if (cin.fail()) //in case the abvoe fails, e.g., ten dollor five cents...
   {
        cout <<"Wrong input types. Try again:\n";
        cin.clear(); //clear the error flags in cin 
        cin.ignore (2048,'\n'); //ignore everthing in the input buffer, up to 2048 char, 
                //up to the newline char =< ignore the rest of the line
        wrongInput = true;
   }
   else
        wrongInput = false;
} while (wrongInput); 

Answer 1

Code:

CODE:

#include<bits/stdc++.h>

using namespace std;

const string space = "";

const string single_digit[] = { space, "One ", "Two ", "Three ", "Four ", "Five ",

"Six ", "Seven ", "Eight ", "Nine ", "Ten ", "Eleven ",

"Twelve ", "Thirteen ", "Fourteen ", "Fifteen ",

"Sixteen ", "Seventeen ", "Eighteen ", "Nineteen " };

const string ten[] = { space, space, "Twenty ", "Thirty ", "Forty ", "Fifty ",

"Sixty ", "Seventy ", "Eighty ", "Ninety " };

string convert2word(int num, string s)

{

// if n is zero

if (num == 0) {

return space;

}

// split n if it is more than 19

if (num > 19) {

return ten[num / 10] + single_digit[num % 10] + s;

}

else {

return single_digit[num] + s;

}

}

string numberToWords(unsigned long long int num)

{

// string to store word representation of given number

string result;

// this handles digits at ones & tens place

result = convert2word((num % 100), "");

if (num > 100 && num % 100) {

result = result;

}

// this handles digit at hundreds place

result = convert2word(((num / 100) % 10), "Hundred ") + result;

// this handles digits at thousands & tens thousands place

result = convert2word(((num / 1000) % 100), "Thousand ") + result;

return result;

}

int countDecimal(double x)

{

stringstream ss;

ss << abs(x-(long long int)x);

string s;

ss >> s;

return s.length()-2;

  

}

int main(int argc,char* argv[]){

double dollar_amount;

char response;

char choice;

bool run = true;

int a;

while(run){

mainmenu:cout<<"PrintDollar"<<"\n";

cout<<"Enter the dollar amount"<<"\n";

while(!(cin>>dollar_amount)){

cin.clear();

cin.ignore(123,'\n');

cout<<"Error !! Please Enter the Valid Amount\n";

goto mainmenu;

}

cout <<"\nIt's "<<numberToWords(abs(dollar_amount));

double dollar_amount1=abs(dollar_amount);

double dollar_amount2 = dollar_amount1 - int(dollar_amount1);

if(countDecimal(dollar_amount)==1){

cout<<"and "<<dollar_amount2*10<<"/10";

}else{

cout<<"and "<<dollar_amount2*100<<"/100";

}

do{

cout<<"\nTry again(y/n)"<<endl;

cin >> choice;

choice = tolower(choice);

}while (choice != 'n' && choice != 'y');

if(choice =='n'){

run = false;

}

  

}

cout<<"Bye!\n";

return 0;

}

Output Screenshot:

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