Suppose 50% of the registered voters in a country are Republican.
If a sample of 629 voters is selected, what is the probability that the sample proportion of Republicans will differ from the population proportion by less than 4%? Round your answer to four decimal places.
Solution:-
The probability that the sample proportion of Republicans will differ from the population proportion by less than 4% is 0.9556

p1 = 0.50 - 0.04 = 0.46
p2 = 0.50 + 0.04 = 0.54
By applying normal distribution:-

z1 = - 2.01
z2 = 2.01
P( -2.01 < z < 2.01) = P(z > -2.01) - P(z > 2.01)
P( -2.01 < z < 2.01) = 0.9778 - 0.0222
P( -2.01 < z < 2.01) = 0.9556
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