Question

In C Programming

Adding to your program in part A, go through the command line arguments and find the largest and smallest arguments by alphabetical order. Note that you should not need to sort your arguments, but instead compare them and save the smallest and largest strings as you go through. For example, if called with ./reverse one two three:

It would display the output for part A:

            Three two one

And then it would display

  The smallest string was: one

     The largest string was: two

This is program part A:

#include<stdio.h>

int main(int argc, char *argv[])

{

//argc tell the total number of argument passed

////run the for loop for the number of arguments in decresing order

for(int i = argc-1; i>0; i--)

{

//display the argument in reverse order

printf("%s ", argv[i]);

}

printf("\n");

return 0;

}

Answer 1

#include<stdio.h>

int main(int argc, char *argv[])

{

//argc tell the total number of argument passed

////run the for loop for the number of arguments in decresing order
char min=*argv[1],max=*argv[1];
for(int i = argc-1; i>0; i--)

{

//display the argument in reverse order

printf("%s ", argv[i]);

}
for(int i = 2; i<argc; i++){
   if(min>*argv[i])
       min=*argv[i];
   if(max<*argv[i])
       max=*argv[i];

}
printf("\nMax : %c\nMin : %c",max,min);

return 0;

}

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