Question

Please do in Java with the code available for copy :)

Write a computer program that prompts the user for one number, n for the number of items in the array to sort, and create and sort 1000 different arrays of this size timing the run to get an average time to sort an array of this size. Then do the following:

Initiate a variable running_time to 0

Create a for loop that iterates 1000 times.

In the body of the loop,

Create an array of n random integers

Get the time and set this to start-time (notice the sort is started after each array is built. You want to time the srt process only). You will have to figure out what the appropriate command is in the programming language you are using to find the time (Important: Do not start the timer until after the array is created).

Use selection sort to sort the array

Get the time and set this to end-time Subtract start-time from end-time and add the result to total_time

Once the program has run, note

The number of items sorted

The average running time for each array (total_time/1000)

Repeat the process using 500, 2500 and 5000 as the size of the array.

Answer 1

java code:

import java.util.Random;
import java.util.Scanner;

public class SelectionSortDriver {

  
public static void main(String[] args) {
  
Scanner sc = new Scanner(System.in);
Random rn = new Random();
  
int n,sort=0;
  
long startTime ,endTime,totaltime=0;
  
//get array size
System.out.println("Enter the array size: ");
n=sc.nextInt();
  
int[] arr= new int[n];
  
//run 1000 times
for(int k=0;k<1000;k++){
  
//random no
for(int m=0;m<n;m++)
arr[m]= rn.nextInt();

startTime= System.nanoTime();
//selection sort
for (int i = 0; i < n-1; i++)
{
// check the elements
int min_idx = i;
for (int j = i+1; j < n; j++)
if (arr[j] < arr[min_idx])
min_idx = j;

// Swap the order or element
  
int temp = arr[min_idx];
arr[min_idx] = arr[i];
arr[i] = temp;
sort++;
}
//endtime
endTime= System.nanoTime();
totaltime +=endTime-startTime; //running time
  
}
  
//print the message
System.out.println("The number of items sorted: "+sort);

System.out.println("The average running time for each array: "+(totaltime/n/1000000.0)+"ms");
  
}
  
  
}
output:

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