Question

A solenoid used to produce magnetic fields for research purposes is 2.1 m long, with an inner radius of 30 cm and 1300 turns of wire. When running, the solenoid produced a field of 1.4 T in the center. Given this, how large a current does it carry? Express your answer in kiloamperes.

Answer 1

as the magnetic field in solenoid is given by,

B = μ° * N * I / L

where B is the magnetic field, N is the total number of turns, I is the current in the solenoid and L is the length of the solenoid.

now putting all the known values,

1.4 = (4π * 10^-7) * 1300 * I / 2.1

now solving for current ,

I = 1.4 * 2.1 / (1300 * 4 * π * 10^-7)

I = 1799.68 A

I = 1.79 kilo amperes

so, the solenoid carry 1.79 kilo amperes current in it.