My (small) water heater holds 35 lb of water at 55 F. How many BTU would be needed to raise it to a toasty 135 F? Ignore any heat lost to the heater body
Heat required to raise the temperature is given by,
Q = m*cpdT
where m is the mass of water (lb)
cp is its specific heat (=1.001 BTU/lb-F)
dT is the change in temperature
Q = 35*1.001*(135-55)
Q = 2802.8 BTU
My (small) water heater holds 35 lb of water at 55 F. How many BTU would...
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