A lab discovers a recessive mutation in fruit flies that makes them appear hairy, and they breed a true-breeding line of flies with this mutation. A different lab independently identifies a recessive mutation that causes hairy flies. What experiment, and what results, would lead you to conclude that the two mutations occur in the same gene? What results would lead you to conclude that the two mutations occur in two different genes?
A 3rd lab independently discovers a mutant that is also hairy, but unlike at Lab 1 and 2, they are unable to produce a true-breeding line. When they try to cross two hairy flies, 2/3 of the offspring are hairy, and 1/3 have the wildtype phenotype. When they cross a Lab 3 hairy fly to a normal fly, half of the offspring are hairy, and half are normal. What is a possible explanation for these results? What are the genotypes of these two crosses (hairy x hairy, and hairy x normal)?
sorry for the extremely long question!
Ans1.
The first part of the question, where we have a true breeding line of mutated flies lab 1 and true breeding line of another mutated breed in another lab, can be solved in the following way.
We know that as the disease is due to a recessive mutation then both of the alleles in the mutated ( hairy ) flies.
Exp1.
Now if the mutated fly from the Lab1 is bred with the mutated fly from the Lab2.
Result1.
If in case both the mutation are on the same gene, then in this case all the progenies would be mutated as there would be no unmutated allele of that gene because all the alleles of the same genes are mutated in both the flies.
If the mutations are not on the same gene. Then none of the progenies will be mutated as no progeny would get the mutated form of both alleles of a particular gene.
Ans 2.
The hairy fly in Lab 3 is not a true breeding line and hence must be having one mutated and one unmutated allele of that gene.
Now as they bred two such hairy flies they are able to provide us a result that we get for a dominant trait/mutation.This can also be confirmed by the second test in which they breed the hairy fly with non mutated ones.
All the above evidences show that the mutation in the fly of Lab3 is a dominant trait.
/****************/ The following answer is dependent on the state of mutation ( homogeneous or Heterogeneous) I'll be considering heterogeneous state of mutatio.*************************************/
In case of the Hairy cross hairy breeding
1. Hairy - 3/4
2. Non Hairy - 1/4
In case of hairy cross normal breeding
1. Hairy - 1/2
2. Non-hairy - 1/2
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