A 20.21 mL aliquot of a Pb2+ solution, containing excess Pb2+, was added to 11.50 mL...
A 20.21 mL aliquot of a Pb2+ solution, containing excess Pb2+, was added to 11.50 mL of a 2,3-dimercapto-1-propanol (BAL) solution of unknown concentration, forming the 1:1 Pb2+ –BAL complex. The excess Pb2+ was titrated with 0.0136 M EDTA, requiring 8.21 mL to reach the equivalence point. Separately, 40.35 mL of the EDTA solution was required to titrate 31.75 mL of the Pb2+ solution. Calculate the BAL concentration, in molarity, of the original 11.50 mL solution.
Homework Answers
Add Answer to:
A 20.21 mL aliquot of a Pb2+ solution, containing excess Pb2+,
was added to 11.50 mL...
A 24.34 mL aliquot of a Pb2 solution, containing excess Pb2+, was added to 11.50 mL...
A 24.34 mL aliquot of a Pb2 solution, containing excess Pb2+, was added to 11.50 mL of a 2,3-dimercapto-1-propanol (BAL) solution of unknown concentration, forming the 1:1 Pb2+-BAL complex. The excess Pb2+ was titrated with 0.0157 M EDTA, requiring 9.88 mL to reach the equivalence point. Separately, 39.89 mL of the EDTA solution was required to titrate 32.75 mL of the Pb2+ solution. Calculate the BAL concentration, in molarity, of the original 11.50 mL solution concentration:
Please help! Will rate. A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 56.5...
Please help! Will rate.
A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 56.5 mL of 0.0600 M EDTA. Titration of the excess unreacted EDTA required 13.3 mL of 0.0100 M Ca. The Cd2t was displaced from EDTA by the addition of an excess of CN. Titration of the newly freed EDTA required 11.2 mL of 0.0100 M Ca2+. What are the concentrations of Cd2+ and Mn2+ in the original solution? M Mn2+ concentration: M Cd2 concentration: A...
A 25.0 mL aliquot of 0.0440 M EDTA was added to a 49.0 mL solution containing...
A 25.0 mL aliquot of 0.0440 M EDTA was added to a 49.0 mL solution containing an unknown concentration of V3+. All of the V3+ present in the solution formed a complex with EDTA, leaving an excess of EDTA in solution. This solution was back-titrated with a 0.0340 M Ga3+ solution until all of the EDTA reacted, requiring 11.0 mL of the Ga3+ solution. What was the original concentration of the V3+ solution?
A 25.0 mL aliquot of 0.05600.0560 M EDTAEDTA was added to a 40.040.0 mL solution containing...
A 25.0 mL aliquot of 0.05600.0560 M EDTAEDTA was added to a 40.040.0 mL solution containing an unknown concentration of V3+V3+. All of the V3+V3+ present in the solution formed a complex with EDTAEDTA, leaving an excess of EDTAEDTA in solution. This solution was back-titrated with a 0.03300.0330 M Ga3+Ga3+ solution until all of the EDTAEDTA reacted, requiring 10.010.0 mL of the Ga3+Ga3+ solution. What was the original concentration of the V3+V3+ solution?
10.5 Zn and Ni?' both react quantitatively with EDTA (Y) Zn2+ + Y4 → ZnY- Ni2+ + + + NIY The reagent 2,3-dimercapto...
10.5 Zn and Ni?' both react quantitatively with EDTA (Y) Zn2+ + Y4 → ZnY- Ni2+ + + + NIY The reagent 2,3-dimercapto-1-propanol (Z) reacts with the zinc-EDTA complex to liberate EDTA but it does not react with the nickel-EDTA complex. ZnY + Z - ZnZ+Y4 NiY+Z-NR. 50.00 mL of a sample solution that contains Ni and Zn? are mixed with 50.00 mL of 0.01981 M EDTA. The excess EDTA is titrated with 0.02010 M Mg, requiring 12.42 mL. Then,...
A titration was performed to standardize an EDTA solution. a) A 25.00 mL aliquot of a...
A titration was performed to standardize an EDTA solution. a) A 25.00 mL aliquot of a standard solution containing 0.01500 M Ca2+ required 42.87 mL of EDTA to reach the endpoint. The molarity of the EDTA solution is: ________ M b) That same EDTA solution was then used to titrate an unknown hard water sample. A 40.00 mL aliquot of unknown hard water required 34.21 mL of EDTA solution to reach a distinct endpoint. The concentration of Ca2+ ions (assuming...
1. A 10.00 mL aliquot of 0.010 M CaCO3 is titrated with 18.22 mL of EDTA...
1. A 10.00 mL aliquot of 0.010 M CaCO3 is titrated with 18.22 mL of EDTA solution. What is the EDTA molarity? 2. A 250.0 mL water sample requires 30.85 mL of the EDTA solution from question 1 to reach the calmagite endpoint. What was the molarity of the hard metal ions in the water sample? 3. If the metal ions in the water sample of question 2 are assumed to be Ca2+ from CaCO3, express the concentration in ppm...
A 1.000-mL aliquot of a solution containing Cu2* and Ni2+ is treated with 25.00 mL of...
A 1.000-mL aliquot of a solution containing Cu2* and Ni2+ is treated with 25.00 mL of a 0.04152 M EDTA solution. The solution is then back titrated with 0.02204 M Zn2 solution at a pH of 5. A volume of 16.29 mL of the Zn2+ solution was needed to reach the xylenol orange end point. A 2.000-mL aliquot of the Cu2 and N solution is fed through an ion-exchange column that retains NP. The Cu2" that passed through the column...
A 1.000-mL aliquot of a solution containing Cu2 and Ni2 is treated with 25.00 mL of...
A 1.000-mL aliquot of a solution containing Cu2 and Ni2 is treated with 25.00 mL of a 0.04328 M EDTA solution. The solution is then back titrated with 0.02246 M Zn2 solution at a pH of 5. A volume of 21.60 mL of the Zn2 solution was needed to reach the xylenol orange end point. A 2.000-mL aliquot of the Cu2 and Ni2 solution is fed through an ion-exchange column that retains Ni2 . The Cu2 that passed through the...
10.6 10.00 mL of a sample of a solution containing Feand Co are added to 100...
10.6 10.00 mL of a sample of a solution containing Feand Co are added to 100 mL of pH 4.5 buffer and then titrated to a Cu-PAN endpoint with 18.82 mL of 0.05106 M EDTA. Then, 25.00 mL of the same of the same solution are added to 100 mL of pH 4.5 buffer along with 10 mL of 1 M potassium fluoride, which is added to mask the Fe'. This solution was titrated to a Cu-PAN endpoint with 13.40...
A 24.34 mL aliquot of a Pb2 solution, containing excess Pb2+, was added to 11.50 mL of a 2,3-dimercapto-1-propanol (BAL) solution of unknown concentration, forming the 1:1 Pb2+-BAL complex. The excess Pb2+ was titrated with 0.0157 M EDTA, requiring 9.88 mL to reach the equivalence point. Separately, 39.89 mL of the EDTA solution was required to titrate 32.75 mL of the Pb2+ solution. Calculate the BAL concentration, in molarity, of the original 11.50 mL solution concentration:
Please help! Will rate.
A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 56.5 mL of 0.0600 M EDTA. Titration of the excess unreacted EDTA required 13.3 mL of 0.0100 M Ca. The Cd2t was displaced from EDTA by the addition of an excess of CN. Titration of the newly freed EDTA required 11.2 mL of 0.0100 M Ca2+. What are the concentrations of Cd2+ and Mn2+ in the original solution? M Mn2+ concentration: M Cd2 concentration: A...
10.5 Zn and Ni?' both react quantitatively with EDTA (Y) Zn2+ + Y4 → ZnY- Ni2+ + + + NIY The reagent 2,3-dimercapto-1-propanol (Z) reacts with the zinc-EDTA complex to liberate EDTA but it does not react with the nickel-EDTA complex. ZnY + Z - ZnZ+Y4 NiY+Z-NR. 50.00 mL of a sample solution that contains Ni and Zn? are mixed with 50.00 mL of 0.01981 M EDTA. The excess EDTA is titrated with 0.02010 M Mg, requiring 12.42 mL. Then,...
A 1.000-mL aliquot of a solution containing Cu2* and Ni2+ is treated with 25.00 mL of a 0.04152 M EDTA solution. The solution is then back titrated with 0.02204 M Zn2 solution at a pH of 5. A volume of 16.29 mL of the Zn2+ solution was needed to reach the xylenol orange end point. A 2.000-mL aliquot of the Cu2 and N solution is fed through an ion-exchange column that retains NP. The Cu2" that passed through the column...
10.6 10.00 mL of a sample of a solution containing Feand Co are added to 100 mL of pH 4.5 buffer and then titrated to a Cu-PAN endpoint with 18.82 mL of 0.05106 M EDTA. Then, 25.00 mL of the same of the same solution are added to 100 mL of pH 4.5 buffer along with 10 mL of 1 M potassium fluoride, which is added to mask the Fe'. This solution was titrated to a Cu-PAN endpoint with 13.40...
Most questions answered within 3 hours.
-
Where is the error in this code sequence?
String s1 = "Hello";
String s2 = "ello";...
asked 10 months ago -
Financial data for Joel de Paris, Inc., for last year
follow:
Joel de Paris, Inc.
Balance...
asked 10 months ago -
Consider this reaction:
Al2(SO4)3 (aq)+ BaCl3
(aq) Al2Cl6 (aq)- +
3BaSO4(s) . What is the...
asked 10 months ago -
Suppose that Savneet is considering increasing her
recent random sample from 20 car rentals to 40...
asked 10 months ago -
Trucks arrive at an unloading terminal at an average rate of 120
per hour.
Trucks arrive...
asked 10 months ago -
Why are methanol and ethanol completely soluble in water while
octanol is not very little soluble....
asked 10 months ago -
A facilities manager at a university reads in a research report
that the mean amount of...
asked 10 months ago -
When the CuSO4 is rehydrated by adding water to the anhydrous
compound, is this an endothermic...
asked 10 months ago -
A ray of sunlight is passing from diamond into crown glass; the
angle of incidence is...
asked 10 months ago -
A block of mass 0.249 kg is placed on top of a light, vertical
spring of...
asked 10 months ago -
how do the kidneys compensate in the presences of acidosis
a) trigger hyperventilate
b) reserve acid...
asked 10 months ago -
Question 501 pts
The rental rate of capital to the firm increases. Which of the
following...
asked 10 months ago