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Jeff walks 8 km North and then 5 km in a direction of 60 degrees East...

Jeff walks 8 km North and then 5 km in a direction of 60 degrees East of North. Find his displacement (straight line distance) from his starting point.

Note that on an X-Y graph, North is in the +Y direction (90 degrees CCW from the +X axis) and 60 degrees East of North is at +30 degrees on the X-Y graph.

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