Question

A sample of argon gas occupies a volume of 7.67 L at 57.0°C and 317 torr. If the volume of the gas sample is decreased to 5.38 L, while its temperature is decreased to 5.0°C, the resulting gas pressure will be torr.

Answer 1

Ans :

Using the relation P1V1 T2 = P2 V2 T1

P1 = 317 torr = 0.417105 atm

V1 = 7.67 L

T1 = 57.0 C = 330.15 K

V2 = 5.38 L

T2 = 5.0 C = 278.15 K

putting values :

= 0.417105 x 7.67 x 278.15 = P2 x 5.38 x 330.15

= 889.8 = 1776.207 x P2

P2 = 0.5009 atm

So pressure in torr = 0.5009 x 760 torr

= 380.8 torr