A sample of hydrogen gas occupies a volume of 9.64 L at 58.0°C and 312 torr. If the volume of the gas sample is decreased to 8.05 L, while its temperature is decreased to –9.0°C, the resulting gas pressure will be torr.
Initial Final
V1 = 9.64L V2 = 8.05L
P1 = 312torr P2 =
T1 = 58+273 = 331K T2 = -9+273 = 264K
P1V1/T1 = P2V2/T2
P2 = P1V1T2/T1V2
= 312*9.64*264/(331*8.05)
= 298 torr
The pressure of gas = 298 torr >>>>>answer
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