Question

A sample of gas initially occupies 3.50 L at a pressure of 795 torr at 32°C. What will the temperature be if the pressure is changed to 4.00 atm, and the volume is changed to 1.50 L?

Answer 1

Initially V = 3.50 L P = 795 foot = 795 alm 760 Ti = 32+273 = 305k and, T,=? V₂ = 1,50 L P = 4 alm Piv, = nRT, P. Vi = unst unst 4X1.50 795X 3.50 → 595 * 350 - 4k 760 X305 = 0.012 = - 4 0.012 = T2 = 500k Hence, Temperature will be 500k