1.) A 0.010 g solution of sodium salicylate (molar mass = 160.11 g/mol) was dissolved in 100 mL of water. A 5.00 mL aliquot of this concentrated solution was diluted to 100 mL. The molarity of the new dilute sodium salicylate solution is __?__ x10^-5 M
1.) A 0.010 g solution of sodium salicylate (molar mass = 160.11 g/mol) was dissolved in...
An unknown amount of a compound with a molecular mass of 284.04 g/mol is dissolved in a 10 mL volumetric flask. A 1.00 mL aliquot of this solution is transferred to a 25 mL volumetric flask, and enough water is added to dilute to the mark. The absorbance of this diluted solution at 347 nm is 0.472 in a 1.000 cm cuvet. The molar absorptivity for this compound at 347 nm is ?347=6023 M−1cm−1. What is the concentration of the...
An unknown amount of a compound with a molecular mass of 294.46 g/mol is dissolved in a 10 mL volumetric flask. A 1.00 mL aliquot of this solution is transferred to a 25 mL volumetric flask, and enough water is added to dilute to the mark. The absorbance of this diluted solution at 343 nm is 0.456 in a 1.000 cm cuvette. The molar absorptivity for this compound at 343 nm is €343 = 5721 M-?cm-1. What is the concentration...
4. What is the mass % of NaCl if 15 g sodium chloride are dissolved in 374 g H2O? (Hint: don't forget that solution mass = solute + solvent mass.) 5. What mass of acetic acid (HC2H302 = 60 g/mol) must be dissolved in 1340 g H2O to produce a 2.75 m solution? 6. What is the new volume of a solution if 437 mL of a .968 M solution are diluted to a .315 M solution? 7. One solution...
An unknown amount of a compound with a molecular mass of 270.93 g/mol is dissolved in a 10-mL volumetric flask. A 1.00-mL aliquot of this solution is transferred to a 25-mL volumetric flask and e water is added to dilute to the mark. The absorbance of this diluted solution at 339 nm is 0.517 in a 1 cm cuvette. The molar absorptivity for this compound at 339 nm is esso- 5835 M-1cm-1 (a) What is the concentration of the compound...
An unknown amount of a compound with a molecular mass of 274.11 g/mol 274.11 g/mol is dissolved in a 10 mL volumetric flask. A 1.00 mL aliquot of this solution is transferred to a 25 mL volumetric flask, and enough water is added to dilute to the mark. The absorbance of this diluted solution at 325 nm 325 nm is 0.523 0.523 in a 1.000 cm cuvet. The molar absorptivity for this compound at 325 nm 325 nm is ?...
A 5.9957 g sample of Na, CrO, (MW = 161.97 g/mol) is dissolved in 1000.0 mL of water. Assume the solution has a density of 1.00 g/mL What is the concentration of Na* (MW = 22.9898 g/mol) in the solution in units of molarity (M)? concentration: М What is the concentration of Na+ in the solution in units of parts per thousand (ppt)? concentration: ppt A 50.0 mL aliquot of the solution is then diluted to a final volume of...
3a. Calculate the molar mass (in g/mol) of an unknown 1:1 electrolyte if 0.482 g dissolved in 223.1 mL of water at 74.75 °C has an osmotic pressure of 54.4 mmHg. R = 0.082058 L⋅atm⋅mol−1⋅K−1. 1.00 atm = 760 mmHg. Report your answer to THREE significant figures. 3b. Calculate the required mass of an unknown nonelectrolyte (ℳ = 131.5599 g/mol) dissolved in 140.1 g of solvent that gives a solution that boils at 36.04 °C. The boiling point of the...
A compound with a molecular mass of 292.16 g/mol was dissolved in a 5-mL volumetric flask. A 1.00-mL aliquot was withdrawn, placed in a 10-mL volumetric flask, and diluted to the mark. The absorbance at 340 nm was 0.427 in a 1.00-cm cuvette. The molar absorptivity at 340 nm is ε340 = 6130 M-1 cm-1. (a) Calculate the concentration of the compound in the cuvette. (b) What was the concentration of the compound in the 10-mL volumetric flask and the...
Table 1. Sodium Acetate Solution Data Mass of Sodium Acetate (g) Volume of Sodium Acetate (mL) Concentration of Sodium Acetate Solution (M) 4 100 ?? Show your work for the calculation of the concentration (in molarity) the sodium acetate solution in Table 1 (in Question 2 above). Include units. NOTE: The molar mass of sodium acetate is 82.0343 g/mol.
A 6.04 g sample of a solid containing Ni is dissolved in 20.0 mL water. A 5.00 mL aliquot of this solution is diluted to 100.0 mL and analyzed in the lab. The analyzed solution was determined to contain 6.88 ppm Ni . Determine the molar concentration of Ni in the 20.0 mL solution. *concentration= ? M Determine the mass, in grams, of Ni in the original sample. *mass= ? g Determine the weight percent of Ni in the sample....