[ 12–Phenobarbitalis C12H12N2O3,what is the mass in grams of one molecule?(Atomic weights:c=12.01,o=16.00,n=14.01,h=1.008
[ 12–Phenobarbitalis C12H12N2O3,what is the mass in grams of one molecule?(Atomic weights:c=12.01,o=16.00,n=14.01,h=1.008
Homework Answers
Molar mass C12H12N2O3 = 12 * (molar mass C) + 12 * (molar mass H) + 2 * (molar mass N) + 3 * (molar mass O)
Molar mass C12H12N2O3 = 12 * (12.01 g/mol) + 12 * (1.008 g/mol) + 2 * (14.01 g/mol) + 3 * (16.00 g/mol)
Molar mass C12H12N2O3 = 144.12 g/mol + 12.096 g/mol + 28.02 g/mol + 48.00 g/mol
Molar mass C12H12N2O3 = 232.236 g/mol
mass of one molecule of C12H12N2O3 = (molar mass C12H12N2O3) / (Avogadro's number)
mass of one molecule of C12H12N2O3 = (232.236 g/mol) / (6.022 x 1023 molecules/mol)
mass of one molecule of C12H12N2O3 = 3.856 x 10-22 g/molecule
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[ 12–Phenobarbitalis C12H12N2O3,what is the mass in grams of one
molecule?(Atomic weights:c=12.01,o=16.00,n=14.01,h=1.008
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