Let P(A) = 0.6, P(B) = 0.3, and P(A∪BC) = 0.1. Calculate P(A|B).
P(A
Bc ) = P(A) + P(B) - P(A
Bc )
0.1 = 0.6 + 0.3 - P(A
Bc )
P(A
Bc ) = 0.8
Now
P(A
Bc ) = P(A) - P(A
B)
0.8 = 0.6 - P(A
B)
P(A
B) = 0.2
Therefore
P(A \ B) = P(A
B) / P(B)
= 0.2 / 0.3
= 2/3
= 0.6667
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1. A Markov chain {X,,n0 with state space S0,1,2 has transition probability matrix 0.1 0.3 0.6 P=10.5 0.2 0.3 0.4 0.2 0.4 If P(X0-0)-P(X0-1) evaluate P[X2< X4]. 0.4 and P 0-2) 0.2. find the distribution of X2 and